To identify the most stable conformer of (Z)-pent-2-ene, let's analyze the structures based on the stereochemistry and stability criteria.

(Z) Configuration: In (Z)-pent-2-ene, the configuration indicates that the higher priority groups on the double bond's carbon atoms are on the same side. For alkenes, according to Cahn-Ingold-Prelog priority rules, higher atomic number priorities are considered first.

Let's apply Gauche Interaction and Steric Hindrance criteria to determine the stability of the given conformers:

Analysis of Stability:

• The most stable conformer in (Z) configuration should have the least steric hindrance and the substituents aligned to minimize any torsional strain.
• For alkenes, stability often comes from avoiding gauche interactions and keeping bulky groups separated.

Reviewing the options:

• The conformers include various arrangements of groups around the central double bond of (Z)-pent-2-ene.
• The correct answer is structured such that the bulky methyl groups are on opposite ends of the plane, thus minimizing steric hindrance while maintaining the (Z) configuration.

Correct Structure:

This diagram represents the most stable structure as the methyl groups are positioned to reduce interaction. It effectively satisfies the (Z) configuration where priority groups (like methyl) are aligned on the same side of the double bond. This arrangement minimizes steric strain and torsional interaction.

Conclusion: Upon evaluating each structural option for steric strain and correct (Z)-placement, the indicated structure is indeed the most stable for (Z)-pent-2-ene, meeting all stability conditions with minimized interaction of larger alkyl groups.