(A) The power of a lens is the ability of the lens to converge or diverge the incident rays.
(B) S.I unit of the power of a lens is dioptre while focal length is in centimetres
(C) For a lens of larger focal length, power is smaller
(D) In any combination of lenses, the power of combination is not algebraic addition of power of combined lenses
Choose the correct answer from the options given below:
This question tests the understanding of the concept of lens power, its units, and its relationship with focal length and combinations of lenses.
This statement accurately defines the power of a lens. The power quantifies how strongly a lens converges or diverges light. A lens with higher power bends light more sharply. Thus, statement (A) is correct.
The S.I. unit of the power of a lens is indeed the dioptre (D). However, the formula relating power ($P$) and focal length ($f$) is $P = \frac{1}{f}$, where $f$ must be in meters (m) for the power to be in dioptres. While focal length is often measured in centimetres, the S.I. unit is meters. Therefore, stating that the S.I. unit for focal length is centimetres makes this statement technically incorrect in the context of the standard definition and calculation.
For example, if focal length $f = 1 \text{ m}$, then $P = \frac{1}{1 \text{ m}} = 1 \text{ D}$. If $f = 20 \text{ cm} = 0.2 \text{ m}$, then $P = \frac{1}{0.2 \text{ m}} = 5 \text{ D}$.
Thus, statement (B) is incorrect.
The power ($P$) of a lens is inversely proportional to its focal length ($f$). The relationship is given by the formula $P = \frac{1}{f}$, where $f$ is measured in meters. This inverse relationship means that as the focal length increases, the power decreases, and vice versa. For instance, a lens with a focal length of 2 meters has a power of $0.5$ D ($\frac{1}{2}$), while a lens with a focal length of 0.5 meters has a power of $2$ D ($\frac{1}{0.5}$).
Thus, statement (C) is correct.
When multiple lenses are placed in contact or in close proximity, the total power of the combination is found by the algebraic sum of the powers of the individual lenses. If $P_1, P_2, P_3, \dots$ are the powers of the individual lenses, the total power $P_{total}$ is given by $P_{total} = P_1 + P_2 + P_3 + \dots$. This principle applies regardless of whether the lenses are converging or diverging (positive or negative power).
Thus, statement (D) is incorrect.
Based on the analysis, statements (A) and (C) are correct, while statements (B) and (D) are incorrect.
Therefore, the correct option is the one that includes only statements (A) and (C).
The graph correctly representing the variation of image distance v for a convex lens of focal length f versus object distance u is:
Two slits are made 0.1 mm apart, and the screen is placed 2 m away. The fringe separation when a light of wavelength 500 nm is used is:
Resolving power of a telescope can be increased by increasing:
Match List - I with List - II.
| List - I | List - II |
|---|---|
| (A) Contracting of Eye ball | (I) Myopia |
| (B) Controls the shape of eye lens | (II) Cornea |
| (C) Elongation of eye ball | (III) Ciliary Muscle |
| (D) Control the light entering in eyes | (IV) Hypermetropia |
Choose the correct answer from the options given below:
Four lenses of focal length ±5cm and ±200cm are available for making a telescope. To produce the largest magnification, the focal length of the eyepiece should be: