Resolving power of a telescope can be increased by increasing:
Diameter of Objective lens
Resolving power of a telescope refers to its ability to distinguish between two objects that are very close together. A higher resolving power means the telescope can show finer details and separate objects that appear as a single blurry point with lower resolving power.
This capability is limited by the wave nature of light and the phenomenon of diffraction. When light from distant objects enters the telescope's objective lens (or mirror), it diffracts, creating a pattern rather than a sharp point image. The size of this diffraction pattern determines how close two points can be before their patterns overlap so much that they cannot be distinguished as separate.
The theoretical resolving power of a telescope is primarily determined by two factors:
The minimum angular separation ($\Delta \theta$) between two point objects that a telescope can resolve is given by the Rayleigh criterion:
$$\Delta \theta = \frac{1.22 \lambda}{D}$$
where:
Resolving power is inversely proportional to the minimum resolvable angle ($\Delta \theta$). Therefore, resolving power is proportional to $\frac{1}{\Delta \theta}$.
So, resolving power $\propto \frac{1}{1.22 \lambda / D} \propto \frac{D}{\lambda}$.
This formula tells us that to increase the resolving power of a telescope, you should:
Let's examine each option provided based on the formula for resolving power:
To increase the resolving power of a telescope, the most effective method among the options is to increase the diameter of the objective lens. A larger objective lens collects more light and reduces the effects of diffraction, allowing for finer detail and better separation of close objects.
| Factor | Affects Resolving Power? | Relationship with Resolving Power | Affects Magnification? | Relationship with Magnification (Simple Refracting Telescope) |
|---|---|---|---|---|
| Diameter of Objective Lens ($D$) | Yes | Resolving Power $\propto D$ | No | N/A |
| Wavelength of Light ($\lambda$) | Yes | Resolving Power $\propto 1/\lambda$ | No | N/A |
| Focal Length of Objective Lens ($f_o$) | No | N/A | Yes | Magnification $\propto f_o$ |
| Focal Length of Eyepiece ($f_e$) | No | N/A | Yes | Magnification $\propto 1/f_e$ |
| Diameter of Eyepiece | No | N/A | No (affects field of view) | N/A |
It's important to distinguish between resolving power and magnification. Magnification makes objects appear larger, but if the telescope doesn't have enough resolving power, the magnified image will simply be a larger blur. High resolving power is essential for seeing fine details, regardless of how much the image is magnified.
The diameter of the objective lens (aperture) is the single most critical factor determining both the resolving power and the light-gathering ability of a telescope. A larger aperture collects more light, allowing you to see fainter objects, and provides higher resolving power, allowing you to see finer details.
While theoretically, decreasing wavelength or increasing diameter increases resolving power, there are practical limits. Using shorter wavelengths like UV or X-rays requires different detector technology and telescopes must be placed outside the Earth's atmosphere. Increasing the diameter of the objective lens makes the telescope significantly larger, heavier, and more expensive to build and maintain. Atmospheric turbulence ("seeing") also limits the achievable resolving power from ground-based telescopes, often below the theoretical limit set by the objective diameter.
The graph correctly representing the variation of image distance v for a convex lens of focal length f versus object distance u is:
Two slits are made 0.1 mm apart, and the screen is placed 2 m away. The fringe separation when a light of wavelength 500 nm is used is:
Match List - I with List - II.
| List - I | List - II |
|---|---|
| (A) Contracting of Eye ball | (I) Myopia |
| (B) Controls the shape of eye lens | (II) Cornea |
| (C) Elongation of eye ball | (III) Ciliary Muscle |
| (D) Control the light entering in eyes | (IV) Hypermetropia |
Choose the correct answer from the options given below:
Four lenses of focal length ±5cm and ±200cm are available for making a telescope. To produce the largest magnification, the focal length of the eyepiece should be:
Which of the following statements are correct?
(A) When light rays undergo two internal reflections inside a raindrop, a secondary rainbow is formed.
(B) The angle between the emergent ray and the angle of the prism is called the angle of deviation.
(C) Light undergoes successive total internal reflections as it moves through an optical fiber.
(D) A telescope provides angular magnification of distant objects.
(E) A simple magnifier is a diverging lens of small focal length.
Choose the correct answer from the options given below: