A. S$^{2-}$
B. C$^{4-}$
C. Mg$^{2+}$
D. O$^{-}$
E. Al$^{3+}$
Choose the correct answer from the options given below:
Isoelectronic species are atoms or ions that possess the same number of electrons. This means they have identical electronic configurations.
The number of electrons in an ion is calculated by taking the atomic number (number of protons, which equals electrons in a neutral atom) and adjusting for the charge.
| Species | Atomic Number (Z) | Charge | Total Electrons |
|---|---|---|---|
| A. S$^{2-}$ | 16 | -2 | $16 + 2 = 18$ |
| B. C$^{4-}$ | 6 | -4 | $6 + 4 = 10$ |
| C. Mg$^{2+}$ | 12 | +2 | $12 - 2 = 10$ |
| D. O$^{-}$ | 8 | -1 | $8 + 1 = 9$ |
| E. Al$^{3+}$ | 13 | +3 | $13 - 3 = 10$ |
Based on the electron counts:
Therefore, the species C$^{4-}$, Mg$^{2+}$, and Al$^{3+}$ (B, C, and E) are isoelectronic as they all contain 10 electrons.
The correct option is the one listing species B, C, and E.
| LIST-I | LIST-II |
|---|---|
| A. Alkaline Earth metals | I. s - block |
| B. Transition Elements | II. p - block |
| C. Transuranic Elements | III. d - block |
| D. Metalloid | IV. f - block |