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Question

Which of the following numbers is divisible by 36 ?  

This question was previously asked in
SSC CGL 2023 (Tier-II) Paper 1 Previous Year Paper (26-Oct-2023) (Shift-1)
The correct answer is

55512

Finding Numbers Divisible by 36

To determine if a number is divisible by 36, we can use divisibility rules. Since $36 = 4 \times 9$ and 4 and 9 are coprime (they have no common factors other than 1), a number is divisible by 36 if and only if it is divisible by both 4 and 9.

Divisibility Rules Explained

  • Divisibility by 4: A number is divisible by 4 if the number formed by its last two digits is divisible by 4.
  • Divisibility by 9: A number is divisible by 9 if the sum of its digits is divisible by 9.

Checking Each Option for Divisibility by 36

Let's apply the divisibility rules for 4 and 9 to each given option:

Option 1: 8840

  • Divisibility by 4: The last two digits are 40. Since $40 \div 4 = 10$, 8840 is divisible by 4.
  • Divisibility by 9: The sum of the digits is $8 + 8 + 4 + 0 = 20$. Since 20 is not divisible by 9, 8840 is not divisible by 9.
  • Conclusion: Since 8840 is not divisible by 9, it is not divisible by 36.

Option 2: 1542

  • Divisibility by 4: The last two digits are 42. Since $42 \div 4$ leaves a remainder (e.g., $42 = 4 \times 10 + 2$), 1542 is not divisible by 4.
  • Conclusion: Since 1542 is not divisible by 4, it is not divisible by 36. We don't need to check for divisibility by 9.

Option 3: 96272

  • Divisibility by 4: The last two digits are 72. Since $72 \div 4 = 18$, 96272 is divisible by 4.
  • Divisibility by 9: The sum of the digits is $9 + 6 + 2 + 7 + 2 = 26$. Since 26 is not divisible by 9, 96272 is not divisible by 9.
  • Conclusion: Since 96272 is not divisible by 9, it is not divisible by 36.

Option 4: 55512

  • Divisibility by 4: The last two digits are 12. Since $12 \div 4 = 3$, 55512 is divisible by 4.
  • Divisibility by 9: The sum of the digits is $5 + 5 + 5 + 1 + 2 = 18$. Since $18 \div 9 = 2$, 55512 is divisible by 9.
  • Conclusion: Since 55512 is divisible by both 4 and 9, it is divisible by 36.

Based on the analysis, only 55512 is divisible by 36.

Number Divisible by 4 (Check last 2 digits) Divisible by 9 (Check sum of digits) Divisible by 36 (Both must be Yes)
8840 Yes (40 is div by 4) No (Sum=20, not div by 9) No
1542 No (42 is not div by 4) - No
96272 Yes (72 is div by 4) No (Sum=26, not div by 9) No
55512 Yes (12 is div by 4) Yes (Sum=18, div by 9) Yes

Revision Table: Divisibility Rules

Divisible by Rule Example
2 Ends in 0, 2, 4, 6, or 8 128 (ends in 8)
3 Sum of digits is divisible by 3 123 (1+2+3=6, 6 is div by 3)
4 Last two digits form a number divisible by 4 116 (16 is div by 4)
5 Ends in 0 or 5 150 (ends in 0)
6 Divisible by both 2 and 3 132 (ends in 2, sum=6)
9 Sum of digits is divisible by 9 162 (1+6+2=9, 9 is div by 9)
10 Ends in 0 140 (ends in 0)
11 Alternating sum of digits is divisible by 11 121 (1-2+1=0, 0 is div by 11)

Additional Information: Combined Divisibility Rules

When checking divisibility by a composite number (a number with more than two factors, like 36), you can break it down into its prime factors or coprime factors. For example:

  • To check divisibility by 6, check divisibility by 2 and 3 (since 2 and 3 are coprime factors of 6).
  • To check divisibility by 10, check divisibility by 2 and 5 (since 2 and 5 are coprime factors of 10).
  • To check divisibility by 12, check divisibility by 3 and 4 (since 3 and 4 are coprime factors of 12).
  • To check divisibility by 15, check divisibility by 3 and 5 (since 3 and 5 are coprime factors of 15).

Using coprime factors is important. For example, checking divisibility by 12 cannot be done by checking divisibility by 2 and 6, because 2 and 6 are not coprime (they share a common factor of 2).

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