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Question

Which of the following is the correct match of the column A with column-B?

Column-A

(Physical Property)

Column-B

(Unit)

i.Electric currenta.Tesla
ii.Voltageb.Farad
iii.Capacitancec.Ampere
iv.Magnetic fieldd.Volt

This question was previously asked in
SSC CGL 2023 (Tier-II) Paper 1 Previous Year Paper (26-Oct-2023) (Shift-1)
The correct answer is

i - c, ii - d, iii - b, iv - a

Understanding Physical Properties and Their Units

This question asks us to match common physical properties related to electricity and magnetism with their standard units. Identifying the correct unit for each property is fundamental in physics and electrical engineering.

Matching Column A (Physical Property) with Column B (Unit)

Let's analyze each physical property listed in Column A and identify its corresponding unit from Column B.

  • i. Electric current: Electric current is the flow of electric charge. Its standard unit is the Ampere (\(\text{A}\)). Looking at Column B, 'c. Ampere' matches electric current.
  • ii. Voltage: Voltage, also known as electric potential difference, is the potential energy difference per unit charge between two points. Its standard unit is the Volt (\(\text{V}\)). Looking at Column B, 'd. Volt' matches voltage.
  • iii. Capacitance: Capacitance is the ability of a conductor or system of conductors to store electric charge. Its standard unit is the Farad (\(\text{F}\)). Looking at Column B, 'b. Farad' matches capacitance.
  • iv. Magnetic field: Magnetic field (specifically, magnetic flux density) is a vector field that describes the magnetic influence of electric currents and magnetic materials. Its standard unit is the Tesla (\(\text{T}\)). Looking at Column B, 'a. Tesla' matches magnetic field.

Summary of Correct Matches

Based on the analysis above, the correct matches are:

  • i. Electric current \(\rightarrow\) c. Ampere
  • ii. Voltage \(\rightarrow\) d. Volt
  • iii. Capacitance \(\rightarrow\) b. Farad
  • iv. Magnetic field \(\rightarrow\) a. Tesla

We can represent these matches in a table:

Column A (Physical Property) Column B (Unit) Match
i. Electric current c. Ampere i - c
ii. Voltage d. Volt ii - d
iii. Capacitance b. Farad iii - b
iv. Magnetic field a. Tesla iv - a

Analyzing the Options

Now let's compare our correct matches (i - c, ii - d, iii - b, iv - a) with the given options:

  1. i - c, ii - d, iii - b, iv - a
  2. i - c, ii - a, iii - b, iv - d
  3. i - d, ii - c, iii - b, iv - a
  4. i - c, ii - d, iii - a, iv - b

Option 1 exactly matches our derived correct pairings.

Conclusion

The correct matching of physical properties with their units is i - c, ii - d, iii - b, iv - a.

Revision Table: Physical Properties and Units

Physical Property Symbol SI Unit Unit Symbol
Electric Current \(I\) Ampere \(\text{A}\)
Voltage (Potential Difference) \(V\) or \(\Delta V\) Volt \(\text{V}\)
Capacitance \(C\) Farad \(\text{F}\)
Magnetic Field (Magnetic Flux Density) \(\mathbf{B}\) Tesla \(\text{T}\)

Additional Information: Understanding Units

Units are essential in physics as they provide a standard way to measure physical quantities. The International System of Units (SI) is the modern form of the metric system and is widely used globally.

  • Ampere (\(\text{A}\)): Defined based on the flow of electric charge. One ampere is approximately \(6.2415 \times 10^{18}\) elementary charges (like electrons) passing a point per second.
  • Volt (\(\text{V}\)): Defined as the potential difference between two points of a conductor carrying a current of one ampere when the power dissipated between these points is one watt. \(1 \text{ V} = 1 \text{ J/C}\) (Joule per Coulomb).
  • Farad (\(\text{F}\)): Defined as the capacitance of a capacitor in which a difference of potential of one volt produces a static electricity charge of one coulomb. \(1 \text{ F} = 1 \text{ C/V}\) (Coulomb per Volt).
  • Tesla (\(\text{T}\)): Defined as the magnetic flux density equal to one weber per square meter. It's a large unit; sometimes the gauss (\(1 \text{ G} = 10^{-4} \text{ T}\)) is used in other unit systems. \(1 \text{ T} = 1 \text{ N/(A}\cdot\text{m)}\) (Newton per Ampere-meter).

Knowing these fundamental units is crucial for solving problems in electricity and magnetism.

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