The standard equation for a hyperbola centered at the origin with its transverse axis along the x-axis is:
$ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 $
The vertices are given as $(\pm a, 0)$ and the foci are given as $(\pm c, 0)$.
From the given information:
Now, we calculate the squares of these values:
For a hyperbola, the relationship between $a$, $b$, and $c$ is $c^2 = a^2 + b^2$. We can use this to find $b^2$:
$ 9 = 4 + b^2 $
Solving for $b^2$:
$ b^2 = 9 - 4 = 5 $
Substitute the values of $a^2$ and $b^2$ into the standard equation:
$ \frac{x^2}{4} - \frac{y^2}{5} = 1 $
This matches Option 3.