Which of the following is a rational number?
Solution: \(32 = 2^5\), so \(\sqrt[5]{32} = 2\) (rational). The 3rd, 4th, 6th roots give \(2^{5/3},\ 2^{5/4},\ 2^{5/6}\) — all irrational.
∴ \(\sqrt[5]{32}\)
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