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Question

Which of the following expressions for a vector potential $\vec{A}$ DOES NOT represent a uniform magnetic field of magnitude $B_0$ along the $z$-direction?

The correct answer is
$\vec{A} = \left( \frac{B_0x}{2} , \frac{B_0y}{2} , 0 \right)$

Vector Potential and Magnetic Field Basics

The magnetic field ($ \vec{B} $) can be derived from the vector potential ($ \vec{A} $) using the curl operation: $ \vec{B} = \nabla \times \vec{A} $ A uniform magnetic field of magnitude $ B_0 $ along the z-direction is represented as $ \vec{B} = (0, 0, B_0) $.

Curl Calculation for Uniform Magnetic Field

The curl of a vector field $ \vec{A} = (A_x, A_y, A_z) $ is given by: $ \nabla \times \vec{A} = \left( \frac{\partial A_z}{\partial y} - \frac{\partial A_y}{\partial z}, \frac{\partial A_x}{\partial z} - \frac{\partial A_z}{\partial x}, \frac{\partial A_y}{\partial x} - \frac{\partial A_x}{\partial y} \right) $ For the field to be $ \vec{B} = (0, 0, B_0) $, the following conditions must be met:

  • $ \frac{\partial A_z}{\partial y} - \frac{\partial A_y}{\partial z} = 0 $
  • $ \frac{\partial A_x}{\partial z} - \frac{\partial A_z}{\partial x} = 0 $
  • $ \frac{\partial A_y}{\partial x} - \frac{\partial A_x}{\partial y} = B_0 $

In all provided options, $ A_z = 0 $ and $ A_x, A_y $ are independent of $ z $. This automatically satisfies the first two conditions. Therefore, we only need to evaluate the third condition, $ \frac{\partial A_y}{\partial x} - \frac{\partial A_x}{\partial y} $, for each option.

Evaluating Vector Potential Expressions

Analysis of Option 1: $ \vec{A} = (0, B_0x, 0) $

Here, $ A_x = 0 $ and $ A_y = B_0x $. The z-component of the curl is: $ \frac{\partial A_y}{\partial x} - \frac{\partial A_x}{\partial y} = \frac{\partial (B_0x)}{\partial x} - \frac{\partial (0)}{\partial y} = B_0 - 0 = B_0 $ This expression yields $ \vec{B} = (0, 0, B_0) $.

Analysis of Option 2: $ \vec{A} = (-B_0y, 0, 0) $

Here, $ A_x = -B_0y $ and $ A_y = 0 $. The z-component of the curl is: $ \frac{\partial A_y}{\partial x} - \frac{\partial A_x}{\partial y} = \frac{\partial (0)}{\partial x} - \frac{\partial (-B_0y)}{\partial y} = 0 - (-B_0) = B_0 $ This expression yields $ \vec{B} = (0, 0, B_0) $.

Analysis of Option 3: $ \vec{A} = \left( \frac{B_0x}{2} , \frac{B_0y}{2} , 0 \right) $

Here, $ A_x = \frac{B_0x}{2} $ and $ A_y = \frac{B_0y}{2} $. The z-component of the curl is: $ \frac{\partial A_y}{\partial x} - \frac{\partial A_x}{\partial y} = \frac{\partial (\frac{B_0y}{2})}{\partial x} - \frac{\partial (\frac{B_0x}{2})}{\partial y} = 0 - 0 = 0 $ This expression yields $ \vec{B} = (0, 0, 0) $, which is not a uniform magnetic field of magnitude $ B_0 $ along the z-direction.

Analysis of Option 4: $ \vec{A} = \left( -\frac{B_0y}{2} , \frac{B_0x}{2} , 0 \right) $

Here, $ A_x = -\frac{B_0y}{2} $ and $ A_y = \frac{B_0x}{2} $. The z-component of the curl is: $ \frac{\partial A_y}{\partial x} - \frac{\partial A_x}{\partial y} = \frac{\partial (\frac{B_0x}{2})}{\partial x} - \frac{\partial (-\frac{B_0y}{2})}{\partial y} = \frac{B_0}{2} - (-\frac{B_0}{2}) = B_0 $ This expression yields $ \vec{B} = (0, 0, B_0) $.

Conclusion: Non-Uniform Field Representation

The expression that does not represent a uniform magnetic field $ \vec{B} = (0, 0, B_0) $ is Option 3, as it results in a zero magnetic field ($ \vec{B} = \vec{0} $).

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Important Questions from Magnetostatics Ampere's Law Vector Potential

  1. Consider a particle of mass $m = 9.0 \times 10^{-5} \text{ kg}$ and charge $q = 3.0 \times 10^{-4} \text{ C}$ in a uniform electromagnetic field $\vec{E} = 2\hat{x} \text{ V.m}^{-1}$, $\vec{B} = 3\hat{z} \text{ V.m}^{-2}\text{.s}$. The particle is released from the coordinates $(0, 5\text{ m}, 0)$ at time $t = 0$. Starting from initial speed zero, it comes back to the $y$-axis for the first time at time $t$. The value of $t$ in seconds (rounded off to two decimal places) is _____
  2. The wire loop shown in the figure carries a steady current $I$. Each straight section of the loop has length $d$. A part of the loop lies in xy plane and the other part is tilted at $30^\circ$ with respect to the xz plane. The magnitude of the magnetic dipole moment of the loop (in appropriate units) is

  3. A linear magnetic material in the form of a cylinder of radius $R$ and length $L$ is placed with its axis parallel to the $z$ axis. The cylinder has uniform magnetization $\vec{M} \hat{k}$. Which of the following option(s) is/are correct?
  4. Consider an isolated magnetized sphere of radius $R$ with a uniform magnetization $\vec{M}$ along the positive $z$ direction, with the north and south poles of the sphere lying on the $z$ axis. It is given that the magnetic field inside the sphere is $\vec{B} = \frac{2\mu_0}{3} \vec{M}$, where $\mu_0$ is the permeability of vacuum. Which of the following statements is(are) CORRECT?
  5. An infinitely long cylinder of radius $R$ carries a frozen-in magnetization $\vec M = ke^{-s^2} \hat z$, where $k$ is a constant and $s$ is the distance from the axis of cylinder. The magnetic permeability of free space is $\mu_o$. There is no free current present anywhere. The magnetic flux density ($\vec B$) inside the cylinder is

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