The wire loop shown in the figure carries a steady current $I$. Each straight section of the loop has length $d$. A part of the loop lies in xy plane and the other part is tilted at $30^\circ$ with respect to the xz plane. The magnitude of the magnetic dipole moment of the loop (in appropriate units) is
To solve this problem, we need to calculate the magnetic dipole moment of the loop carrying a steady current \(I\). The loop consists of straight sections, each of length \(d\). The key to solving this problem is understanding the geometry of the loop and its orientation in the 3D plane.
The magnetic dipole moment \(\mathbf{m}\) of a current loop is given by the formula:
m = I \cdot A
where \(I\) is the current and \(A\) is the area of the loop.
In this problem, the loop consists of two distinct areas: one in the xy-plane and one tilted at \(30^\circ\) in the xz-plane.
Based on the calculations and conceptual understanding, the correct answer is \(Id^2\), which matches the given correct option.

**Conclusion:** The magnitude of the magnetic dipole moment of the loop is \(Id^2\), based on the combination of areas taking into account their contributions through orientation and tilt.
An infinitely long cylinder of radius $R$ carries a frozen-in magnetization $\vec M = ke^{-s^2} \hat z$, where $k$ is a constant and $s$ is the distance from the axis of cylinder. The magnetic permeability of free space is $\mu_o$. There is no free current present anywhere. The magnetic flux density ($\vec B$) inside the cylinder is
The temperature $T$ dependence of magnetic susceptibility $\chi$ (Column I) of certain magnetic materials (Column II) are given below. Which of the following option is/are correct?
Column I | Column II | |
| 1. | ![]() | (P) Diamagnetic |
| 2. | ![]() | (Q) Paramagnetic |
| 3. | ![]() | (R) Ferromagnetic |
| 4. | ![]() | (S) Antiferromagnetic |