What would be the smaller of the two angles formed by the hour hand and the minute hand at 4 : 52 p.m.?
166°
This problem involves calculating the angle between the hour hand and the minute hand of a standard 12-hour analog clock at a specific time, 4:52 p.m. To solve this, we need to determine the position (angle from the 12 mark) of both hands at that exact moment.
Let's analyze the movement of each hand:
We will calculate the angle of each hand relative to the 12 o'clock mark, moving clockwise.
At 4:52 p.m., the minute hand is exactly at the 52-minute mark. Its angle from the 12 is:
Angle of minute hand = Number of minutes $\times$ Angle per minute
Angle of minute hand = $52 \times 6^\circ = 312^\circ$
At 4:52 p.m., the hour hand has moved past the 4 o'clock mark. Its position depends on both the hour (4) and the additional minutes (52).
Total angle of the hour hand from the 12 o'clock mark:
Angle of hour hand = Angle at 4:00 + Additional angle in 52 minutes
Angle of hour hand = $120^\circ + 26^\circ = 146^\circ$
The angle between the hour hand and the minute hand is the absolute difference between their positions:
Angle = $| \text{Angle of Hour Hand} - \text{Angle of Minute Hand} |$
Angle = $| 146^\circ - 312^\circ |$
Angle = $| -166^\circ |$
Angle = $166^\circ$
When two hands are on a clock face, they divide the 360 degrees of the circle into two angles. The angle we calculated ($166^\circ$) is one of these angles. The other angle is $360^\circ$ minus the calculated angle.
Other angle = $360^\circ - 166^\circ = 194^\circ$
The question asks for the smaller of the two angles. Comparing $166^\circ$ and $194^\circ$, the smaller angle is $166^\circ$.
| Hand | Calculation | Angle from 12 |
|---|---|---|
| Minute Hand | $52 \times 6^\circ$ | $312^\circ$ |
| Hour Hand | $(4 \times 30^\circ) + (52 \times 0.5^\circ) = 120^\circ + 26^\circ$ | $146^\circ$ |
| Angle between hands | $|146^\circ - 312^\circ|$ | $166^\circ$ |
| Other Angle | $360^\circ - 166^\circ$ | $194^\circ$ |
| Smaller Angle | Minimum of $166^\circ$ and $194^\circ$ is $166^\circ$ | |
The smaller angle formed by the hour hand and the minute hand at 4:52 p.m. is $166^\circ$. This matches option 4.
| Concept | Formula / Value | Notes |
|---|---|---|
| Total degrees on clock | $360^\circ$ | Full circle |
| Degrees per hour mark | $30^\circ$ | $360^\circ / 12$ hours |
| Minute hand speed | $6^\circ$ per minute | $360^\circ / 60$ minutes |
| Hour hand speed | $0.5^\circ$ per minute | $30^\circ / 60$ minutes |
| Angle at H hours M minutes | $| (30 \times \text{H}) + (0.5 \times \text{M}) - (6 \times \text{M}) |$ | Angle from 12 for hour hand is $30H + 0.5M$; Angle from 12 for minute hand is $6M$. |
| Alternative formula | $| 30 \times \text{H} - 5.5 \times \text{M} |$ | Simplified version |
| Smaller Angle | Calculate angle A. If $A > 180^\circ$, smaller angle is $360^\circ - A$. Otherwise, it's A. | Two angles are formed by the hands. |
Clock angle problems are a common type of quantitative aptitude question. They can involve various scenarios:
Understanding the relative speeds of the hour and minute hands is crucial for solving these problems efficiently. The minute hand gains $6^\circ - 0.5^\circ = 5.5^\circ$ on the hour hand every minute.
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