All Exams Test series for 1 year @ ₹349 only
Question

What will be the length of longest diagonal of the cuboid having length 13 cm width 11 cm and height 20 cm?

The correct answer is

26.27 cm

Calculating the Longest Diagonal of a Cuboid

A cuboid is a three-dimensional solid shape bounded by six rectangular faces. It is also known as a rectangular prism. The longest diagonal of a cuboid is a line segment connecting two opposite vertices that do not lie on the same face.

Formula for the Longest Diagonal

The length of the longest diagonal (\(d\)) of a cuboid with length (\(l\)), width (\(w\)), and height (\(h\)) is given by the formula derived from extending the Pythagorean theorem to three dimensions:

\[ d = \sqrt{l^2 + w^2 + h^2} \]

Applying the Formula with Given Dimensions

In this problem, we are given the dimensions of the cuboid:

  • Length (\(l\)) = 13 cm
  • Width (\(w\)) = 11 cm
  • Height (\(h\)) = 20 cm

Now, we substitute these values into the formula:

\[ d = \sqrt{(13 \, \text{cm})^2 + (11 \, \text{cm})^2 + (20 \, \text{cm})^2} \]

Calculate the squares of each dimension:

  • \(13^2 = 169\)
  • \(11^2 = 121\)
  • \(20^2 = 400\)

Sum the squared values:

\[ 13^2 + 11^2 + 20^2 = 169 + 121 + 400 = 690 \]

Now, take the square root of the sum:

\[ d = \sqrt{690} \, \text{cm} \]

Calculating the square root of 690 gives an approximate value:

\[ \sqrt{690} \approx 26.2679 \, \text{cm} \]

Rounding this value to two decimal places, we get:

\[ d \approx 26.27 \, \text{cm} \]

Conclusion

The length of the longest diagonal of the cuboid is approximately 26.27 cm.

Comparing this result with the given options:

  • Option 1: 23.45 cm
  • Option 2: 26.27 cm
  • Option 3: 34.65 cm
  • Option 4: 22.65 cm

The calculated length matches Option 2.

Revision Table: Cuboid Formulas

Concept Formula Description
Volume (V) \(V = l \times w \times h\) Space occupied by the cuboid
Surface Area (SA) \(SA = 2(lw + lh + wh)\) Total area of all faces
Longest Diagonal (d) \(d = \sqrt{l^2 + w^2 + h^2}\) Length of the longest distance between two vertices

Additional Information: Pythagorean Theorem in 3D

The formula for the longest diagonal of a cuboid is a direct application of the Pythagorean theorem in three dimensions. Consider a cuboid with vertices at (0,0,0) and (l,w,h). The distance between these two points is the length of the longest diagonal. Using the distance formula in 3D (which is derived from the Pythagorean theorem), the distance is \(\sqrt{(l-0)^2 + (w-0)^2 + (h-0)^2}\), which simplifies to \(\sqrt{l^2 + w^2 + h^2}\). This shows how the familiar theorem extends from 2D right triangles to 3D rectangular solids.

Was this answer helpful?

Important Questions from Solid Figures

  1. A cone and a hemisphere have equal bases and volumes. What is the ratio of the height of the cone to the radius of the hemisphere?

  2. If the surface area of a sphere is 64 π cm 2, then the volume of the sphere is:

  3. Find the surface area of a sphere of diameter 21 cm. (Use π = \(\frac{{22}}{7}\) )

  4. A cube is 7 cm of an edge and another cube is 14 cm on an edge. The ratios of their surface areas are

  5. Using three distinct points which of the following shapes cannot be formed?

Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App