The given problem is to find the missing term in the alphanumeric series:

\(2A-50, 5Z-46, 8B-42, 11Y-38, ?\)

Let's analyze the pattern in both the numeric and alphabetical parts:

1. Examine the numeric part of the series: \(2, 5, 8, 11, ?\)
2. Notice the increments: \(5 - 2 = 3\), \(8 - 5 = 3\), \(11 - 8 = 3\)
3. The sequence increases by 3 consistently, so the next number will be \(11 + 3 = 14\).
4. Now examine the alphabetical part of the series: \(A, Z, B, Y, ?\)
5. Observe the pattern in alphabet steps: \(A \rightarrow B\) (forward by 1), \(Z \rightarrow Y\) (backward by 1)
6. The pattern alternates between moving forward by 1 letter and backward by 1 letter.
7. Continuing this logic, from \(Y\), the next letter following the pattern is \(C\) (backward by 1).
8. Finally, examine the changes in the subtracted numeric part: \(50, 46, 42, 38, ?\)
9. The sequence decrements by 4 consistently: \(50 - 46 = 4\), \(46 - 42 = 4\), \(42 - 38 = 4\)
10. The next subtraction should be \(38 - 4 = 34\).

Thus, combining all these observations, the term that fits the series is \(14C-34\).

Hence, the correct answer is 14c-34.