What is the value of 5 ÷ 10 of 10 × 4 + 4 ÷ 4 of 4 × 10 + (10 - 4) ÷ 16 × 4?
The question asks us to find the value of a mathematical expression involving several operations: division, 'of', multiplication, addition, subtraction, and parentheses. To correctly solve such an expression, we must follow the standard order of operations, commonly known as BODMAS or PEMDAS.
The BODMAS rule provides a specific sequence for performing operations in an expression:
Division and Multiplication have the same priority and should be performed from left to right. Similarly, Addition and Subtraction have the same priority and should be performed from left to right.
The given expression is:
\(5 \div 10 \text{ of } 10 \times 4 + 4 \div 4 \text{ of } 4 \times 10 + (10 - 4) \div 16 \times 4\)
First, we evaluate the expression inside the brackets:
\((10 - 4) = 6\)
Substitute this value back into the expression:
\(5 \div 10 \text{ of } 10 \times 4 + 4 \div 4 \text{ of } 4 \times 10 + 6 \div 16 \times 4\)
Next, we perform the 'of' operations, which are equivalent to multiplication:
Substitute these values into the expression:
\(5 \div 100 \times 4 + 4 \div 16 \times 10 + 6 \div 16 \times 4\)
Now, we perform all division and multiplication operations from left to right, treating the expression as three separate terms joined by addition:
Term 1: \(5 \div 100 \times 4\)
\(5 \div 100 = \frac{5}{100} = \frac{1}{20}\)
So, Term 1 is \(\frac{1}{20} \times 4 = \frac{4}{20} = \frac{1}{5}\)
Term 2: \(4 \div 16 \times 10\)
\(4 \div 16 = \frac{4}{16} = \frac{1}{4}\)
So, Term 2 is \(\frac{1}{4} \times 10 = \frac{10}{4} = \frac{5}{2}\)
Term 3: \(6 \div 16 \times 4\)
\(6 \div 16 = \frac{6}{16} = \frac{3}{8}\)
So, Term 3 is \(\frac{3}{8} \times 4 = \frac{12}{8} = \frac{3}{2}\)
Substitute these simplified terms back into the expression:
\(\frac{1}{5} + \frac{5}{2} + \frac{3}{2}\)
Finally, we perform the addition:
\(\frac{1}{5} + \frac{5}{2} + \frac{3}{2}\)
First, add the fractions with the same denominator:
\(\frac{5}{2} + \frac{3}{2} = \frac{5 + 3}{2} = \frac{8}{2} = 4\)
Now, add this result to the remaining term:
\(\frac{1}{5} + 4\)
To add a fraction and a whole number, convert the whole number into a fraction with the same denominator:
\(4 = \frac{4 \times 5}{5} = \frac{20}{5}\)
So, the expression becomes:
\(\frac{1}{5} + \frac{20}{5} = \frac{1 + 20}{5} = \frac{21}{5}\)
The final value of the expression is \(\frac{21}{5}\).
| Step | Operation | Expression | Result |
|---|---|---|---|
| 1 | Brackets | \((10 - 4)\) | \(6\) |
| 2 | 'Of' | \(10 \text{ of } 10\), \(4 \text{ of } 4\) | \(100\), \(16\) |
| 3 | Division/Multiplication (Term 1) | \(5 \div 100 \times 4\) | \(\frac{1}{5}\) |
| 3 | Division/Multiplication (Term 2) | \(4 \div 16 \times 10\) | \(\frac{5}{2}\) |
| 3 | Division/Multiplication (Term 3) | \(6 \div 16 \times 4\) | \(\frac{3}{2}\) |
| 4 | Addition | \(\frac{1}{5} + \frac{5}{2} + \frac{3}{2}\) | \(\frac{21}{5}\) |
The calculated value matches option 4.
| Order | Category | Operations |
|---|---|---|
| 1st | Brackets | ( ) |
| 2nd | Of / Orders | of, powers, roots |
| 3rd | Division & Multiplication | \(\div\), \(\times\) (Left to Right) |
| 4th | Addition & Subtraction | \(+\), \(-\) (Left to Right) |
The order of operations is crucial in mathematics to ensure that everyone arrives at the same result for a given expression. Without a standard order, an expression like \(2 + 3 \times 4\) could be interpreted differently: either as \((2 + 3) \times 4 = 5 \times 4 = 20\) or as \(2 + (3 \times 4) = 2 + 12 = 14\). The BODMAS/PEMDAS rule resolves this ambiguity, stipulating that multiplication is performed before addition, leading to the correct result of 14.
PEMDAS is another acronym used in some regions, standing for Parentheses, Exponents, Multiplication, Division, Addition, Subtraction. It represents the same order of operations as BODMAS.
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