The value of \(\frac{{33}}{{40}} + \frac{1}{5}\left[ {\frac{4}{5} - \frac{1}{5} \times \left( {\frac{7}{8} - \frac{5}{4}} \right)} \right] - \frac{4}{5}\) is:
This problem requires us to simplify a mathematical expression involving fractions and different operations. To correctly solve such expressions, we must follow the order of operations, commonly known as BODMAS or PEMDAS.
The expression we need to simplify is: \( \frac{{33}}{{40}} + \frac{1}{5}\left[ {\frac{4}{5} - \frac{1}{5} \times \left( {\frac{7}{8} - \frac{5}{4}} \right)} \right] - \frac{4}{5} \)
The BODMAS rule helps us decide the sequence in which operations should be performed in a mathematical expression. The acronym stands for:
PEMDAS is another version of the rule, where 'P' is Parentheses, 'E' is Exponents, and 'M' and 'D' (Multiplication and Division) and 'A' and 'S' (Addition and Subtraction) are done from left to right.
We solve operations within brackets first, starting from the innermost bracket. Then we proceed with the other operations according to the order.
The innermost bracket contains the expression \( \left( {\frac{7}{8} - \frac{5}{4}} \right) \). To subtract these fractions, we need a common denominator. The least common multiple of 8 and 4 is 8.
Convert \( \frac{5}{4} \) to an equivalent fraction with denominator 8:
\( \frac{5}{4} = \frac{5 \times 2}{4 \times 2} = \frac{10}{8} \)
Now perform the subtraction inside the bracket:
\( \frac{7}{8} - \frac{10}{8} = \frac{7 - 10}{8} = \frac{-3}{8} \)
The expression now becomes:
\( \frac{{33}}{{40}} + \frac{1}{5}\left[ {\frac{4}{5} - \frac{1}{5} \times \left( \frac{-3}{8} \right)} \right] - \frac{4}{5} \)
Inside the square bracket, we have \( \frac{4}{5} - \frac{1}{5} \times \left( \frac{-3}{8} \right) \). According to BODMAS, multiplication comes before subtraction. So, we first calculate \( \frac{1}{5} \times \left( \frac{-3}{8} \right) \).
Multiply the numerators and the denominators:
\( \frac{1}{5} \times \frac{-3}{8} = \frac{1 \times (-3)}{5 \times 8} = \frac{-3}{40} \)
The expression inside the square bracket is now:
\( \frac{4}{5} - \left( \frac{-3}{40} \right) \)
The overall expression is now:
\( \frac{{33}}{{40}} + \frac{1}{5}\left[ \frac{4}{5} - \left( \frac{-3}{40} \right) \right] - \frac{4}{5} \)
We need to calculate \( \frac{4}{5} - \left( \frac{-3}{40} \right) \). Subtracting a negative number is the same as adding the positive number.
\( \frac{4}{5} - \left( \frac{-3}{40} \right) = \frac{4}{5} + \frac{3}{40} \)
To add these fractions, find a common denominator, which is 40.
Convert \( \frac{4}{5} \) to an equivalent fraction with denominator 40:
\( \frac{4}{5} = \frac{4 \times 8}{5 \times 8} = \frac{32}{40} \)
Now perform the addition:
\( \frac{32}{40} + \frac{3}{40} = \frac{32 + 3}{40} = \frac{35}{40} \)
Simplify the fraction \( \frac{35}{40} \) by dividing the numerator and denominator by their greatest common divisor, which is 5.
\( \frac{35 \div 5}{40 \div 5} = \frac{7}{8} \)
So, the value inside the square bracket is \( \frac{7}{8} \). The expression now is:
\( \frac{{33}}{{40}} + \frac{1}{5}\left[ \frac{7}{8} \right] - \frac{4}{5} \)
We need to calculate \( \frac{1}{5} \times \frac{7}{8} \).
\( \frac{1}{5} \times \frac{7}{8} = \frac{1 \times 7}{5 \times 8} = \frac{7}{40} \)
The expression is now:
\( \frac{{33}}{{40}} + \frac{7}{40} - \frac{4}{5} \)
We have \( \frac{{33}}{{40}} + \frac{7}{40} - \frac{4}{5} \).
First, perform the addition \( \frac{{33}}{{40}} + \frac{7}{40} \). Since the denominators are already the same, we just add the numerators:
\( \frac{33}{40} + \frac{7}{40} = \frac{33 + 7}{40} = \frac{40}{40} = 1 \)
The expression simplifies to \( 1 - \frac{4}{5} \).
Now, perform the subtraction \( 1 - \frac{4}{5} \). To subtract these, write 1 as a fraction with denominator 5:
\( 1 = \frac{5}{5} \)
Now subtract:
\( \frac{5}{5} - \frac{4}{5} = \frac{5 - 4}{5} = \frac{1}{5} \)
The final value of the expression is \( \frac{1}{5} \).
| Order | Operation Type | Description |
|---|---|---|
| 1 | Brackets/Parentheses | Simplify everything inside grouping symbols first, starting from the innermost. |
| 2 | Orders/Exponents | Evaluate powers and roots. |
| 3 | Division and Multiplication | Perform division and multiplication from left to right. |
| 4 | Addition and Subtraction | Perform addition and subtraction from left to right. |
When simplifying expressions with fractions, it's important to remember the rules for fraction arithmetic:
Applying these rules carefully, along with the BODMAS order, is key to accurately solving complex fractional expressions.
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