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Question

What is the unit digit of \(3^{68} \times 4^{73} \times 15^{101}\)?

This question was previously asked in
RRB ALP/Technician 2018 CBT 2 Electronics Mechanic Question Paper (23-Jan-2019) (Shift 1)
The correct answer is
0

To find the unit digit of the expression \(3^{68} \times 4^{73} \times 15^{101}\), we need to determine the unit digit of each factor separately and then multiply them.

Unit Digit of Powers

We analyze the unit digit of each term:

Finding Unit Digit of \(3^{68}\)

  • The unit digits of powers of 3 follow a repeating cycle: 3, 9, 7, 1. The cycle length is 4.
  • To find the unit digit of \(3^{68}\), we look at the exponent 68. We find the remainder when 68 is divided by the cycle length, 4.
  • Calculation: \(68 \div 4 = 17\) with a remainder of 0.
  • When the remainder is 0, the unit digit is the last digit in the cycle, which is 1.

Finding Unit Digit of \(4^{73}\)

  • The unit digits of powers of 4 follow a repeating cycle: 4, 6. The cycle length is 2.
  • To find the unit digit of \(4^{73}\), we look at the exponent 73. We find the remainder when 73 is divided by the cycle length, 2.
  • Calculation: \(73 \div 2 = 36\) with a remainder of 1.
  • When the remainder is 1, the unit digit is the first digit in the cycle, which is 4.

Finding Unit Digit of \(15^{101}\)

  • Any positive integer power of a number ending in 5 will always have a unit digit of 5.
  • Therefore, the unit digit of \(15^{101}\) is 5.

Calculate Final Unit Digit

Now, we multiply the unit digits of each factor:

  • Unit digit of \(3^{68}\) is 1.
  • Unit digit of \(4^{73}\) is 4.
  • Unit digit of \(15^{101}\) is 5.

The unit digit of the product \(3^{68} \times 4^{73} \times 15^{101}\) is the unit digit of the product of their unit digits:

Unit digit of \((1 \times 4 \times 5)\)

Calculation: \(1 \times 4 \times 5 = 20\).

The unit digit of 20 is 0.

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  3. The digit in the units place of (34) 9 + (46) 21  - (43) 27  is:

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