The following table shows the marks scored by six students (A–F) in six different subjects S1 to S6 having maximum marks of 160, 160, 120, 120, 200, and 240 respectively. Based on the data in the table, answer the question that follows: Student-wise details of Marks ScoredStudents Marks Scored in Subject S1 (Out of 160) S2 (Out of 160) S3 (Out of 120) S4 (Out of 120) S5 (Out of 200) S6 (Out of 240) A 76 84 66 56 154 144 B 120 100 84 76 136 132 C 128 72 64 70 144 160 D 84 130 96 84 104 168 E 64 128 90 92 174 70 F 70 96 60 56 164 96
The question asks for the ratio of the total marks scored by student B to the total marks scored by student D, based on the provided table of scores across six subjects.
First, let's extract the marks scored by Student B and Student D in each subject:
| Student | S1 | S2 | S3 | S4 | S5 | S6 |
| B | 120 | 100 | 84 | 76 | 136 | 132 |
| D | 84 | 130 | 96 | 84 | 104 | 168 |
To find the total marks scored by Student B, we sum the marks obtained in all six subjects:
Total Marks (B) = Marks(S1) + Marks(S2) + Marks(S3) + Marks(S4) + Marks(S5) + Marks(S6)
Total Marks (B) = $120 + 100 + 84 + 76 + 136 + 132$
Total Marks (B) = $648$
Similarly, we sum the marks obtained by Student D in all six subjects:
Total Marks (D) = Marks(S1) + Marks(S2) + Marks(S3) + Marks(S4) + Marks(S5) + Marks(S6)
Total Marks (D) = $84 + 130 + 96 + 84 + 104 + 168$
Total Marks (D) = $666$
The question requires the ratio of the total marks scored by Student B to the total marks scored by Student D. This can be written as:
Ratio (B : D) = Total Marks (B) : Total Marks (D)
Ratio (B : D) = $648 : 666$
To simplify the ratio $648 : 666$, we need to find the greatest common divisor (GCD) of 648 and 666.
Now, divide both parts of the ratio by the GCD (18):
Simplified Ratio = $\frac{648}{18} : \frac{666}{18}$
Simplified Ratio = $36 : 37$
Therefore, the ratio of the total marks scored by student B to the total marks scored by student D is $36 : 37$.
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If the ratio of the first to second number is 3 : 4 and that of the second to the third number is 8 : 5, and sum of three numbers is 190 then the third number is:
The third proportional to 9 and 15 is:
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