Ethanol Reaction with Sodium: Identifying Products
This question asks about the outcome of reacting ethanol (\(\text{C}_2\text{H}_5\text{OH}\)) with sodium (Na).
Understanding the Chemical Reaction
Sodium is a highly reactive alkali metal. It reacts readily with alcohols, similar to how it reacts with water, but typically less vigorously. In this reaction, the acidic hydrogen atom of the alcohol's hydroxyl (\(\text{-OH}\)) group is replaced by the sodium atom.
- Ethanol's structure allows the hydrogen in the \(\text{-OH}\) group to be substituted.
- Sodium acts as a reducing agent, losing an electron.
Reaction Equation and Products
The balanced chemical equation for the reaction between ethanol and sodium is:
\( 2 \text{C}_2\text{H}_5\text{OH} + 2 \text{Na} \rightarrow 2 \text{C}_2\text{H}_5\text{ONa} + \text{H}_2 \uparrow \)
From the equation, we can identify the products:
- Sodium ethoxide (\(\text{C}_2\text{H}_5\text{ONa}\)): This is the salt formed from ethanol.
- Hydrogen gas (\(\text{H}_2\)): This gas is released during the reaction, indicated by the upward arrow (\(\uparrow\)).
Evaluating the Options
Let's compare the identified products with the given options:
- Option 1: States sodium ethoxide and hydrogen gas evolve. This matches our findings.
- Option 2: Mentions sodium hydroxide and oxygen gas. Incorrect.
- Option 3: Mentions sodium oxide and water. Incorrect.
- Option 4: Mentions sodium carbonate and hydrogen gas. Incorrect (sodium carbonate is not formed).
Therefore, the correct description of the reaction products is provided in Option 1.
Important Questions from Carbon and its Compounds
- What is Tetrachloromethane primarily used for in manufacturing?
- What is the atomic number of Carbon?
The most pure form of carbon among the options is
- Which one of the following forms of carbon is thermodynamically most stable?
