To determine the mean proportional between two numbers, we need to find the square root of the product of those two numbers. Given the numbers are \(8 + 3\sqrt{3}\) and \(16 - 6\sqrt{3}\), we will find the product of these numbers and then its square root.
The formula for the mean proportional \(x\) between two numbers \(a\) and \(b\) is:
\(x = \sqrt{a \cdot b}\)
Substituting the given numbers:
\(a = 8 + 3\sqrt{3}\) and \(b = 16 - 6\sqrt{3}\)
First, we calculate the product:
\(\begin{align*} a \cdot b & = (8 + 3\sqrt{3})(16 - 6\sqrt{3}) \\ & = 8 \cdot 16 + 8 \cdot (-6\sqrt{3}) + 3\sqrt{3} \cdot 16 + 3\sqrt{3} \cdot (-6\sqrt{3}) \\ & = 128 - 48\sqrt{3} + 48\sqrt{3} - 54 \\ & = 128 - 54 \\ & = 74 \end{align*}\)
Now, the mean proportional is:
\(x = \sqrt{74}\)
Thus, the correct answer is: \(\sqrt{74}\)
This matches the correct answer option provided: \(\sqrt{74}\).
The other options given do not equal to the product of the numbers, hence they are incorrect.
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