The following table shows the number of students who appeared in a Common Entrance Test (CET) from six different schools A-F during the years 2020-2022, and the ratio of number of passed (P) to the number of failed (F) students among them. Based on the data in the table, answer the questions: School-wise Appearance of Students in CET during 2020-2022. School 2020 2021 2022 Appeared P ∶ F Appeared P ∶ F Appeared P ∶ F A 1292 11 ∶ 8 1508 7 ∶ 6 1344 3 ∶ 5 B 1694 4 ∶ 7 1690 8 ∶ 5 1904 9 ∶ 8 C 1620 8 ∶ 7 1584 7 ∶ 4 1274 4 ∶ 3 D 1752 7 ∶ 5 1656 11 ∶ 7 1976 7 ∶ 12 E 1740 3 ∶ 2 1452 7 ∶ 4 1430 8 ∶ 5 F 1972 17 ∶ 12 1734 12 ∶ 5 1848 8 ∶ 13
What is the difference between the number of students who passed in the test from School D in the year 2020 and the number of students who failed in the test from School B in the year 2022?
126
Step 1: Number of students passed from School D in the year 2020
Total students appeared from School D in the year 2020 = $1752$
Ratio of passed and failed = $7 : 5$
Sum of ratios = $7 + 5 = 12$
Number of passed students = $\frac{7}{12} \times 1752$
Number of passed students = $7 \times 146 = 1022$
Step 2: Number of failed students from School B in the year 2022
Total students appeared from School B in the year 2022 = $1904$
Ratio of passed and failed = $9 : 8$
Sum of ratios = $9 + 8 = 17$
Number of failed students = $\frac{8}{17} \times 1904$
Number of failed students = $8 \times 112 = 896$
Step 3: Difference between both numbers
Difference = $1022 - 896 = 126$
Thus, the correct option is Option 3 (126).
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