To solve this problem, we need to determine which blocks are dominated by Block 3 and Block 5 in the flow graph derived from the given Three Address Code (TAC). Dominance in a control flow graph implies that a block B is said to dominate another block C if every path from the start block to block C goes through block B.

Let's first break down the given TAC to identify the basic blocks:

1. Block 1: 100: \(t1 = y + 2\)
2. Block 2: 101: \(initial = x/t1\)
3. Block 3:
   • 102: \(limit = 10\)
   • 103: \(\text{if } i > j \text{ goto 105}\)
   • 104: \(\text{goto 111}\)
4. Block 4:
   • 105: \(\text{if } num > b \text{ goto 107}\)
   • 106: \(\text{goto 111}\)
5. Block 5:
   • 107: \(num = limit - 1\)
   • 108: \(b = y + 2\)
   • 109: \(i = i - num\)
   • 110: \(\text{goto 103}\)
6. Block 6:
   • 111: \(j = i - num\)
   • 112: \(k = j + b\)

Now, examining the flow of the control graph:

Block 3 is a branching block due to the conditional jumps in instructions 103 and 104. Block 3's control transfers either to Block 5 (via instruction 103) or Block 6 (via instruction 104).

Block 5 receives control from both Block 4 and Block 3 via instruction 105, and it loops back to Block 3 at instruction 110.

Let's analyze the dominance:

• Dominance of Block 3: Block 3 dominates itself (102-104), as a block always dominates itself. However, because of conditional branching, no other blocks are necessarily dominated by it as all possible branches do not mandatorily pass through Block 3.
• Dominance of Block 5: Block 5 follows the execution of Block 4 and Block 3 but returns the control to Block 3, so it doesn't dominate any block other than itself.

Thus, the correct answer is:

• Block 3: Dominates itself.
• Block 5: Dominates itself.

Therefore, the correct answer from the given options is:

Block 3:3 ; Block 5:5