Wash out in a continuous stirred tank fermenter signifies a state where the rate at which cells are removed from the reactor exceeds their growth rate. The question specifies this critical condition as the dilution rate ($D$) being equal to the maximum specific growth rate ($\mu_{max}$), i.e., $D = \mu_{max}$.
Based on the analysis, the state of wash out ($D = \mu_{max}$) is characterized by:
This corresponds to Option B.
If the rate at which $E. coli$ divides is $0.5 \text{ h}^{-1}$, then its doubling time is _______________ h.
Let $y(t)$ be a bacterial population whose growth is given by
$ \frac{dy}{dt} = \lambda(y + 2) $
where $ \lambda $ is the growth rate constant. If $y(0) = 1$ and $y(1) = 4$, then the value of $ \lambda $ is
If the doubling time of a bacterial population is 3 hours, then its average specific growth rate during this period is _________ $h^{-1}$.
(Round off to two decimal places)