Two years ago the average age of P, Q, R and S was 30 years. On including A, the average present age of all five is 35 years. Then present age of A is
47 years
This problem involves calculating the present age of a person, referred to as 'A', using information about the average ages of a group of people (P, Q, R, and S) at different times.
We are given that the average age of four people (P, Q, R, S) two years ago was 30 years. To find the sum of their ages two years ago, we multiply the average age by the number of people:
Sum of ages of P, Q, R, S (two years ago) = Average age $\times$ Number of people
Sum of ages (two years ago) = $30 \times 4 = 120$ years.
Since the initial average was calculated two years ago, each of the four individuals (P, Q, R, S) is now 2 years older. Therefore, the total increase in their combined age is:
Increase in total age = Number of people $\times$ Number of years passed
Increase = $4 \times 2 = 8$ years.
Now, we can find the sum of the present ages of P, Q, R, and S:
Sum of present ages (P, Q, R, S) = Sum of ages (two years ago) + Increase in total age
Sum of present ages (P, Q, R, S) = $120 + 8 = 128$ years.
When person A is included, the group size becomes 5 people. The problem states that the average present age of these five people (P, Q, R, S, A) is 35 years. The sum of their present ages is:
Sum of ages (P, Q, R, S, A, present) = Average present age $\times$ Number of people
Sum of ages (P, Q, R, S, A, present) = $35 \times 5 = 175$ years.
To find the present age of person A, we subtract the sum of the present ages of P, Q, R, and S from the sum of the present ages of all five people (P, Q, R, S, A):
Present age of A = Sum of ages (P, Q, R, S, A, present) - Sum of present ages (P, Q, R, S)
Present age of A = $175 - 128 = 47$ years.
The present age of person A is 47 years.
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