Two trains started at 7AM from the same point. The first train travelled north at a speed of 80km/h and the second train travelled south at a speed of 100 km/h. The time at which they were 540 km apart is _______________ AM.
Problem Analysis:
The relative speed is the sum of the speeds of the two trains because they are moving in opposite directions.
Relative Speed $= \text{Speed}_1 + \text{Speed}_2$
Relative Speed $= 80 \text{ km/h} + 100 \text{ km/h} = 180 \text{ km/h}$
The time it takes for the trains to be 540 km apart can be calculated using the formula: Time = Distance / Speed.
Time $= \frac{\text{Total Distance}}{\text{Relative Speed}}$
Time $= \frac{540 \text{ km}}{180 \text{ km/h}} = 3 \text{ hours}$
The trains started at 7 AM. They will be 540 km apart after 3 hours.
Final Time = Start Time + Time Taken
Final Time $= 7 \text{ AM} + 3 \text{ hours} = 10 \text{ AM}$
In a 500 m race, P and Q have speeds in the ratio of 3: 4. Q starts the race when P has already covered 140 m.
What is the distance between P and Q (in m) when P wins the race?
A vehicle is moving at a speed of 12 m/s on a level road. It applies emergency brakes and starts to skid without rolling in a straight path. The deceleration of the vehicle is constant after braking and it comes to rest at a distance of 15 m. Assuming, $g = 10$ m/s$^2$, the coefficient of kinetic friction between the tyres and road is _________ [round off to 2 decimal places]