In a 500 m race, P and Q have speeds in the ratio of 3: 4. Q starts the race when P has already covered 140 m.
What is the distance between P and Q (in m) when P wins the race?
This solution details the calculation for the distance between runners P and Q when P finishes a 500 m race, considering their speed ratio and a staggered start for Q.
Let the speeds of runner P and runner Q be $3x$ m/s and $4x$ m/s, respectively, based on the given ratio of 3:4.
P has already covered 140 m when Q starts. The time taken by P to cover this initial distance is:
$t_{P_{140}} = \frac{\text{Distance}}{\text{Speed}_P} = \frac{140 \text{ m}}{3x \text{ m/s}} = \frac{140}{3x} \text{ seconds}$
The total race distance is 500 m. The total time P takes to complete the race from the start is:
$T_P = \frac{\text{Total Distance}}{\text{Speed}_P} = \frac{500 \text{ m}}{3x \text{ m/s}} = \frac{500}{3x} \text{ seconds}$
Q starts at time $t_{P_{140}}$. P finishes at time $T_P$. The duration Q runs is the difference between these times:
$ \text{Duration}_Q = T_P - t_{P_{140}} = \frac{500}{3x} - \frac{140}{3x} = \frac{360}{3x} = \frac{120}{x} \text{ seconds} $
In the duration calculated above, Q covers a distance using their speed:
$ \text{Distance}_Q = \text{Speed}_Q \times \text{Duration}_Q = (4x \text{ m/s}) \times \left(\frac{120}{x} \text{ seconds}\right) = 480 \text{ m} $
When P finishes the race, P is at the 500 m mark. Q has covered 480 m. The distance between them is:
$ \text{Distance between P and Q} = 500 \text{ m} - 480 \text{ m} = 20 \text{ m} $
Therefore, the distance between P and Q when P wins the race is 20 m.
Two cars start at the same time from the same location and go in the same direction. The speed of the first car is 50 km/h and the speed of the second car is 60 km/h. The number of hours it takes for the distance between the two cars to be 20 km is ___________.