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Question

In a 500 m race, P and Q have speeds in the ratio of 3: 4. Q starts the race when P has already covered 140 m. 
What is the distance between P and Q (in m) when P wins the race?

The correct answer is
20

Race Distance Calculation: P vs Q Speed Ratio

This solution details the calculation for the distance between runners P and Q when P finishes a 500 m race, considering their speed ratio and a staggered start for Q.

Step 1: Define Speeds Based on Ratio

Let the speeds of runner P and runner Q be $3x$ m/s and $4x$ m/s, respectively, based on the given ratio of 3:4.

Step 2: Calculate Time for P to Cover Initial Distance

P has already covered 140 m when Q starts. The time taken by P to cover this initial distance is:

$t_{P_{140}} = \frac{\text{Distance}}{\text{Speed}_P} = \frac{140 \text{ m}}{3x \text{ m/s}} = \frac{140}{3x} \text{ seconds}$

Step 3: Determine Time P Takes to Finish the Race

The total race distance is 500 m. The total time P takes to complete the race from the start is:

$T_P = \frac{\text{Total Distance}}{\text{Speed}_P} = \frac{500 \text{ m}}{3x \text{ m/s}} = \frac{500}{3x} \text{ seconds}$

Step 4: Calculate Duration Q Runs Until P Finishes

Q starts at time $t_{P_{140}}$. P finishes at time $T_P$. The duration Q runs is the difference between these times:

$ \text{Duration}_Q = T_P - t_{P_{140}} = \frac{500}{3x} - \frac{140}{3x} = \frac{360}{3x} = \frac{120}{x} \text{ seconds} $

Step 5: Calculate Distance Covered by Q

In the duration calculated above, Q covers a distance using their speed:

$ \text{Distance}_Q = \text{Speed}_Q \times \text{Duration}_Q = (4x \text{ m/s}) \times \left(\frac{120}{x} \text{ seconds}\right) = 480 \text{ m} $

Step 6: Find the Distance Between P and Q at P's Finish

When P finishes the race, P is at the 500 m mark. Q has covered 480 m. The distance between them is:

$ \text{Distance between P and Q} = 500 \text{ m} - 480 \text{ m} = 20 \text{ m} $

Therefore, the distance between P and Q when P wins the race is 20 m.

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Important Questions from Speed Distance and Time

  1. Two cars, P and Q, start from a point X in India at 10 AM. Car P travels North with a speed of 25 km/h and car Q travels East with a speed of 30 km/h. Car P travels continuously but car Q stops for some time after travelling for one hour. If both the cars are at the same distance from X at 11:30 AM, for how long (in minutes) did car Q stop?
  2. A vehicle is moving at a speed of 12 m/s on a level road. It applies emergency brakes and starts to skid without rolling in a straight path. The deceleration of the vehicle is constant after braking and it comes to rest at a distance of 15 m. Assuming, $g = 10$ m/s$^2$, the coefficient of kinetic friction between the tyres and road is  _________ [round off to 2 decimal places]

  3. The distance between Delhi and Agra is 233 km. A car P started travelling from Delhi to Agra and another car Q started from Agra to Delhi along the same road 1 hour after the car P started. The two cars crossed each other 75 minutes after the car Q started. Both cars were travelling at constant speed. The speed of car P was 10 km/hr more than the speed of car Q. How many kilometers the car Q had travelled when the cars crossed each other?
  4. Two trains started at 7AM from the same point. The first train travelled north at a speed of 80km/h and the second train travelled south at a speed of 100 km/h. The time at which they were 540 km apart is  _______________ AM.

  5. From the time the front of a train enters a platform, it takes 25 seconds for the back of the train to leave the platform, while travelling at a constant speed of 54 km/h. At the same speed, it takes 14 seconds to pass a man running at 9 km/h in the same direction as the train. What is the length of the train and that of the platform in meters, respectively?
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