Two cars start at the same time from the same location and go in the same direction. The speed of the first car is 50 km/h and the speed of the second car is 60 km/h. The number of hours it takes for the distance between the two cars to be 20 km is ___________.
Determine the time required for the distance between two cars traveling in the same direction to become 20 km.
The speeds of the two cars are $v_1 = 50$ km/h and $v_2 = 60$ km/h. Since they move in the same direction, the relative speed ($v_{rel}$) at which the distance between them increases is:
$ v_{rel} = v_2 - v_1 $
$ v_{rel} = 60 \text{ km/h} - 50 \text{ km/h} = 10 \text{ km/h} $
The target distance ($D$) is 20 km. The time ($t$) needed to cover this distance at the relative speed is found using the formula $D = v_{rel} \times t$.
$ t = \frac{D}{v_{rel}} $
Substituting the values:
$ t = \frac{20 \text{ km}}{10 \text{ km/h}} $
$ t = 2 \text{ hours} $
Therefore, it takes 2 hours for the distance between the cars to reach 20 km.
In a 500 m race, P and Q have speeds in the ratio of 3: 4. Q starts the race when P has already covered 140 m.
What is the distance between P and Q (in m) when P wins the race?
A vehicle is moving at a speed of 12 m/s on a level road. It applies emergency brakes and starts to skid without rolling in a straight path. The deceleration of the vehicle is constant after braking and it comes to rest at a distance of 15 m. Assuming, $g = 10$ m/s$^2$, the coefficient of kinetic friction between the tyres and road is _________ [round off to 2 decimal places]
Two trains started at 7AM from the same point. The first train travelled north at a speed of 80km/h and the second train travelled south at a speed of 100 km/h. The time at which they were 540 km apart is _______________ AM.