Two similar triangles are \( \triangle ABC \) and \( \triangle LMN \). If the area of \( \triangle ABC = 25 \) cm², the area of \( \triangle LMN = 36 \) cm², and BC = 2.5 cm, then the measure of MN (in cm) is:
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To find the measure of MN, we can use the property of similar triangles where the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. Given:
We need to find MN. Let the side MN be denoted as \( x \).
The ratio of the areas of the triangles is given by:
\[\frac{\text{Area of } \triangle ABC}{\text{Area of } \triangle LMN} = \frac{25}{36}\]
This is equal to the square of the ratio of their corresponding sides:
\[\left(\frac{BC}{MN}\right)^2 = \left(\frac{2.5}{x}\right)^2\]
Thus, we have:
\[\frac{25}{36} = \left(\frac{2.5}{x}\right)^2\]
By taking the square root on both sides, we obtain:
\[\frac{5}{6} = \frac{2.5}{x}\]
Solving for \( x \):
\[x = \frac{2.5 \times 6}{5} = \frac{15}{5} = 3 \, \text{cm}\]
Therefore, the measure of MN is 3 cm.
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