The problem asks for the day of the week $43$ days prior to a Friday.
Days of the week follow a cycle of $7$. To find the day $43$ days ago, we can determine the remainder when $43$ is divided by $7$. This remainder tells us how many days we need to count back from the current day (Friday).
Divide the total number of days ($43$) by the number of days in a week ($7$):
$ 43 \div 7 $
Find the remainder of this division:
$ 43 = (6 \times 7) + 1 $
The remainder is $1$. This means $43$ days is equivalent to $6$ full weeks and $1$ extra day.
Count back from Friday based on the remainder:
Since the remainder is $1$, we need to count back $1$ day from Friday.
One day before Friday is Thursday.
Therefore, $43$ days before Friday, it was Thursday.