Day Calculation: Jan 1, 2001 to Jan 26, 2003
We need to find the day of the week for 26th January, 2003, given that 1st January, 2001 was a Monday.
We can calculate the day shift year by year.
Finding the Day for Jan 1, 2002
The year 2001 has 365 days. Since 365 divided by 7 leaves a remainder of 1 ($365 \mod 7 = 1$), the day of the week shifts forward by 1 day each normal year.
Calculation:
- Number of days in 2001 = 365
- Remainder = $365 \div 7 = 52$ remainder 1
- Therefore, 1st January, 2002 was a Monday + 1 day = Tuesday.
Finding the Day for Jan 1, 2003
The year 2002 also has 365 days (it's not a leap year). The day shifts forward by 1 day again.
Calculation:
- Number of days in 2002 = 365
- Remainder = $365 \div 7 = 52$ remainder 1
- Therefore, 1st January, 2003 was a Tuesday + 1 day = Wednesday.
Finding the Day for Jan 26, 2003
We know that 1st January, 2003 was a Wednesday. We need to find the day for 26th January, 2003.
Calculate the number of days passed from 1st January, 2003 to 26th January, 2003.
Number of days = $26 - 1 = 25$ days.
Now, find the remainder when 25 is divided by 7.
Calculation:
- $25 \div 7 = 3$ remainder 4
This means the day of the week for 26th January, 2003 will be 4 days after Wednesday.
- Wednesday + 1 day = Thursday
- Wednesday + 2 days = Friday
- Wednesday + 3 days = Saturday
- Wednesday + 4 days = Sunday
So, 26th January, 2003 was a Sunday.
Final Answer Determination
Based on the calculation, the day on 26th January, 2003 was Sunday.
Important Questions from Clock and Calendar (Notes)
- From the given options, at what angle are the hands of a clock inclined at 10 minutes to 2 (Smaller angle) ?
- Today is Friday. Before $43$ days, it was?
- How many times starting at 1:00 pm would the minute and hour hands of a clock make an angle of $40^\circ$ with each other in the next 6 hours?
- A man starts his journey at 0100 Hrs local time to reach another country at 0900 Hrs local time on the same date. He starts a return journey on the same night at 2100 Hrs local time to his original place, taking the same time to travel back. If the time zone of his country of visit lags by 10 hours, the duration for which the man was away from his place is
- Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A) : The angle between the two arms of a watch when the time is 3.10 pm, will be 35°
Reason (R) : When the hour arm of the watch is ahead of the minute arm, then angle between the two arms at the time t hour and x minute is $\left[30\left(t-\frac{x}{5}\right)+\frac{x}{2}\right]^\circ$
In the light of the above statements, choose the most appropriate answer from the options given below :
