Coil $C_1$ carries current $I$ in an anti-clockwise direction. Using the right-hand rule, this generates a magnetic field along the common axis directed, let's say, towards the right (positive direction). Coil $C_3$ carries current $I$ in a clockwise direction. This generates a magnetic field along the axis directed towards the left (negative direction).
At the location of coil $C_2$, which is midway, the net magnetic field $B_{net}$ is the difference between the field contributions from $C_1$ ($B_1$) and $C_3$ ($B_3$). We can represent this as $B_{net} = B_1 - B_3$, where $B_1$ and $B_3$ are the magnitudes of the magnetic fields generated by $C_1$ and $C_3$ respectively at $C_2$. The net magnetic flux through $C_2$ is proportional to $B_{net}$.
Let's analyze the effect of the motion described in Option C: $C_1$ moves towards $C_2$ and $C_3$ moves away from $C_2$.
The change in the net magnetic field is $\Delta B_{net} = \Delta B_1 - \Delta B_3$. Substituting the signs of the changes:
$\Delta B_{net} = (+ \text{ve}) - (- \text{ve}) = (+ \text{ve}) + (+ \text{ve})$
This means $\Delta B_{net}$ is definitely positive. Therefore, the net magnetic flux through $C_2$ is increasing in the positive direction (the direction of the field from $C_1$).
According to Lenz's Law, an induced current flows in a direction that opposes the change in magnetic flux that produced it.
Since the net magnetic flux through $C_2$ is increasing in the positive direction, the induced current in $C_2$ must create a magnetic field that opposes this increase. This opposing field must be in the negative direction (opposite to the field from $C_1$).
A clockwise current in coil $C_2$ generates a magnetic field pointing in the negative direction (towards the left, opposing the increasing flux from $C_1$). Therefore, the induced current in $C_2$ will be in the clockwise direction under these conditions.
Three long straight wires carrying current are arranged mutually parallel as shown in the figure. The force experienced by $15 \text{ cm}$ length of wire $Q$ is________.
$(\mu_o = 4\pi \times 10^{-7} \text{ T.m/A})$
The equivalent resistance between the points $A$ and $B$ in the following circuit is $\frac{x}{5} \text{ }\Omega$. The value of $x$ is ________.

A meter bridge with two resistances $R_1$ and $R_2$ as shown in figure was balanced (null point) at 40 cm from the point $P$. The null point changed to 50 cm from the point $P$, when $16 \ \Omega$ resistance is connected in parallel to $R_2$. The values of resistances $R_1$ and $R_2$ are _________.

XPQY is a vertical smooth long loop having a total resistance $R$ where PX is parallel to QY and separation between them is $l$. A constant magnetic field $B$ perpendicular to the plane of the loop exists in the entire space. A rod CD of length $L \ (L > l)$ and mass $m$ is made to slide down from rest under the gravity as shown in figure. The terminal speed acquired by the rod is _________ m/s. (g = acceleration due to gravity)

Three long straight wires carrying current are arranged mutually parallel as shown in the figure. The force experienced by $15 \text{ cm}$ length of wire $Q$ is________.
$(\mu_o = 4\pi \times 10^{-7} \text{ T.m/A})$