There are 9 different rock lizard species, each with a unique colour. Lizards of 2 different species sit on a rock at any given time. The number of possible colour combinations of rock lizards seen together on a rock is _________
(Answer in integer)
The problem requires finding the number of ways to choose 2 different species (and thus colours) from a group of 9 distinct species. Since the order in which the lizards are chosen does not matter, this is a combination problem.
The formula for combinations is used to find the number of ways to choose a subset of items from a larger set without regard to the order of selection. It is denoted as $C(n, k)$ or $\binom{n}{k}$ and calculated as:
$ C(n, k) = \binom{n}{k} = \frac{n!}{k!(n-k)!} $
Where:
In this question:
Substitute these values into the combination formula:
$ C(9, 2) = \binom{9}{2} = \frac{9!}{2!(9-2)!} $
$ C(9, 2) = \frac{9!}{2!7!} $
Calculate the factorials:
$ C(9, 2) = \frac{9 \times 8 \times 7!}{ (2 \times 1) \times 7!} $
Cancel out $7!$:
$ C(9, 2) = \frac{9 \times 8}{2 \times 1} $
$ C(9, 2) = \frac{72}{2} $
$ C(9, 2) = 36 $
The number of possible colour combinations of rock lizards seen together on a rock is 36.
How many ways are there to pack six copies of the same book into four identical boxes, where a box can contain as many as six books ?
Let us assume a person climbing the stairs can take one stair or two stairs at a time. How many ways can this person climb a flight of eight stairs?