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Question

Ten teams participate in a tournament. Every team plays each of the other teams twice. The total number of matches to be played is

The correct answer is
90

Tournament Matches Calculation

This problem involves calculating the total number of matches played in a tournament where every team plays every other team twice.

  1. Determine the number of teams involved. Let $n$ be the number of teams. Given: $n = 10$.

  2. Calculate the number of matches. Each team needs to play against the other $n-1$ teams. Since every team plays each of the other teams twice, we can calculate the total matches using the formula: Total Matches $= n \times (n-1)$

  3. Substitute the value of $n$ into the formula. Total Matches $= 10 \times (10-1)$ Total Matches $= 10 \times 9$ Total Matches $= 90$

Therefore, the total number of matches to be played is 90.

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Important Questions from Combinations

  1. How many ways are there to pack six copies of the same book into four identical boxes, where a box can contain as many as six books ?

  2. Let us assume a person climbing the stairs can take one stair or two stairs at a time. How many ways can this person climb a flight of eight stairs?

  3. There are 9 different rock lizard species, each with a unique colour. Lizards of 2 different species sit on a rock at any given time. The number of possible colour combinations of rock lizards seen together on a rock is _________ 
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  4. There are nine species of Impatiens (balsams) found in laterite plateaus of the northern Western Ghats, each with a distinct colour. If a plateau has exactly 6 species, then the number of possible colour combinations in the plateau is __________. (Answer in integer)
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