This problem involves calculating the number of buffalos based on the total number of heads and feet of different animals.
Each animal has one head. Let the number of buffalos be $x$.
Total Heads = $20 + 10 + 15 + x = 45 + x$
Different animals have different numbers of feet:
Total Feet = (Number of Pigeons $\times$ 2) + (Number of Cows $\times$ 4) + (Number of Dogs $\times$ 4) + (Number of Buffalos $\times$ 4)
Total Feet = $(20 \times 2) + (10 \times 4) + (15 \times 4) + (x \times 4)$
Total Feet = $40 + 40 + 60 + 4x$
Total Feet = $140 + 4x$
The problem states that the total number of feet is 125 more than the total number of heads.
Total Feet = Total Heads + 125
$140 + 4x = (45 + x) + 125$
Simplify the equation:
$140 + 4x = 170 + x$
$4x - x = 170 - 140$
$3x = 30$
$x = \frac{30}{3}$
$x = 10$
Therefore, the number of buffalos is 10.
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