The work function of a metal is $3 \ eV$. The color of the visible light that is required to cause emission of photoelectrons is
Blue
The photoelectric effect describes how electrons are emitted from a material when light shines on it. This happens only if the light's energy is sufficient to overcome the metal's work function, which is the minimum energy required to free an electron.
The work function ($\phi$) of the metal is given as $3 \ eV$.
The energy ($E$) of a photon of light is related to its frequency ($f$) and wavelength ($\lambda$) by the equation $E = hf = \frac{hc}{\lambda}$, where $h$ is Planck's constant and $c$ is the speed of light.
For photoelectron emission to occur, the photon energy must be greater than or equal to the work function: $ E \ge \phi $ So, we need light with energy $E \ge 3 \ eV$.
Different colors of visible light have different energies (and wavelengths). Generally, moving from red to violet, the wavelength decreases, and the photon energy increases:
(Note: These are approximate energy ranges.)
We need light with energy $E \ge 3 \ eV$. Let's compare this requirement with the energy ranges of the given colors:
Blue light is the color required to cause the emission of photoelectrons from a metal with a work function of $3 \ eV$, as its photon energy meets the minimum threshold.
Consider following statements for refraction of light through prism, when angle of deviation is minimum.
A. The refracted ray inside prism becomes parallel to the base.
B. Larger angle prisms provide smaller angle of minimum deviation.
C. Angle of incidence and angle of emergence becomes equal.
D. There are always two sets of angle of incidence for which deviation will be same except at minimum deviation setting.
E. Angle of refraction becomes double of prism angle. Choose the correct answer from the options given below:
The radii of curvature for a thin convex lens are $10 \ cm$ and $15 \ cm$ respectively. The focal length of the lens is $12 \ cm$. The refractive index of the lens material is
In the figure shown below, a resistance of $150.4 \Omega$ is connected in series to an ammeter A of resistance $240 \Omega$. A shunt resistance of $10 \Omega$ is connected in parallel with the ammeter. The reading of the ammeter is __________ mA.

A slanted object AB is placed on one side of convex lens as shown in the diagram. The image is formed on the opposite side. Angle made by the image with principal axis is :

A spherical surface separates two media of refractive indices 1 and 1.5 as shown in figure. Distance of the image of an object 'O', is :
(C is the center of curvature of the spherical surface and R is the radius of curvature)
Consider following statements for refraction of light through prism, when angle of deviation is minimum.
A. The refracted ray inside prism becomes parallel to the base.
B. Larger angle prisms provide smaller angle of minimum deviation.
C. Angle of incidence and angle of emergence becomes equal.
D. There are always two sets of angle of incidence for which deviation will be same except at minimum deviation setting.
E. Angle of refraction becomes double of prism angle. Choose the correct answer from the options given below:
The radii of curvature for a thin convex lens are $10 \ cm$ and $15 \ cm$ respectively. The focal length of the lens is $12 \ cm$. The refractive index of the lens material is
In the figure shown below, a resistance of $150.4 \Omega$ is connected in series to an ammeter A of resistance $240 \Omega$. A shunt resistance of $10 \Omega$ is connected in parallel with the ammeter. The reading of the ammeter is __________ mA.

A slanted object AB is placed on one side of convex lens as shown in the diagram. The image is formed on the opposite side. Angle made by the image with principal axis is :

A spherical surface separates two media of refractive indices 1 and 1.5 as shown in figure. Distance of the image of an object 'O', is :
(C is the center of curvature of the spherical surface and R is the radius of curvature)