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Question

The work function of a metal is $3 \ eV$. The color of the visible light that is required to cause emission of photoelectrons is

The correct answer is

Blue

Understanding Photoelectron Emission

The photoelectric effect describes how electrons are emitted from a material when light shines on it. This happens only if the light's energy is sufficient to overcome the metal's work function, which is the minimum energy required to free an electron.

Work Function and Photon Energy

The work function ($\phi$) of the metal is given as $3 \ eV$.

The energy ($E$) of a photon of light is related to its frequency ($f$) and wavelength ($\lambda$) by the equation $E = hf = \frac{hc}{\lambda}$, where $h$ is Planck's constant and $c$ is the speed of light.

For photoelectron emission to occur, the photon energy must be greater than or equal to the work function: $ E \ge \phi $ So, we need light with energy $E \ge 3 \ eV$.

Photon Energy of Visible Light Colors

Different colors of visible light have different energies (and wavelengths). Generally, moving from red to violet, the wavelength decreases, and the photon energy increases:

  • Red light: Has the longest wavelength and lowest energy (~1.65 to 2.0 eV).
  • Yellow light: Has intermediate energy (~2.2 to 2.4 eV).
  • Green light: Has higher energy (~2.4 to 3.0 eV).
  • Blue light: Has even higher energy (~3.0 to 3.3 eV).
  • Violet light: Has the shortest wavelength and highest energy (~3.3 to 4.0 eV).

(Note: These are approximate energy ranges.)

Determining the Required Light Color

We need light with energy $E \ge 3 \ eV$. Let's compare this requirement with the energy ranges of the given colors:

  • Red light energy is less than $3 \ eV$.
  • Yellow light energy is less than $3 \ eV$.
  • Green light energy is approximately $3 \ eV$ or slightly less, so it might not consistently cause emission.
  • Blue light energy starts at or above $3 \ eV$. Therefore, blue light photons have enough energy to overcome the $3 \ eV$ work function and cause photoelectron emission.

Conclusion

Blue light is the color required to cause the emission of photoelectrons from a metal with a work function of $3 \ eV$, as its photon energy meets the minimum threshold.

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Similar Questions

  1. Consider following statements for refraction of light through prism, when angle of deviation is minimum. 

    A. The refracted ray inside prism becomes parallel to the base. 

    B. Larger angle prisms provide smaller angle of minimum deviation. 

    C. Angle of incidence and angle of emergence becomes equal. 

    D. There are always two sets of angle of incidence for which deviation will be same except at minimum deviation setting. 

    E. Angle of refraction becomes double of prism angle. Choose the correct answer from the options given below:

  2. The radii of curvature for a thin convex lens are $10 \ cm$ and $15 \ cm$ respectively. The focal length of the lens is $12 \ cm$. The refractive index of the lens material is

  3. In the figure shown below, a resistance of $150.4 \Omega$ is connected in series to an ammeter A of resistance $240 \Omega$. A shunt resistance of $10 \Omega$ is connected in parallel with the ammeter. The reading of the ammeter is __________ mA.

  4. A slanted object AB is placed on one side of convex lens as shown in the diagram. The image is formed on the opposite side. Angle made by the image with principal axis is :


  5. A spherical surface separates two media of refractive indices 1 and 1.5 as shown in figure. Distance of the image of an object 'O', is : 
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  6. If the measured angular separation between the second minimum to the left of the central maximum and the third minimum to the right of the central maximum is $30^\circ$ in a single slit diffraction pattern recorded using 628 nm light, then the width of the slit is _________ $\mu$m.
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Important Questions from Optics

  1. Consider following statements for refraction of light through prism, when angle of deviation is minimum. 

    A. The refracted ray inside prism becomes parallel to the base. 

    B. Larger angle prisms provide smaller angle of minimum deviation. 

    C. Angle of incidence and angle of emergence becomes equal. 

    D. There are always two sets of angle of incidence for which deviation will be same except at minimum deviation setting. 

    E. Angle of refraction becomes double of prism angle. Choose the correct answer from the options given below:

  2. The radii of curvature for a thin convex lens are $10 \ cm$ and $15 \ cm$ respectively. The focal length of the lens is $12 \ cm$. The refractive index of the lens material is

  3. In the figure shown below, a resistance of $150.4 \Omega$ is connected in series to an ammeter A of resistance $240 \Omega$. A shunt resistance of $10 \Omega$ is connected in parallel with the ammeter. The reading of the ammeter is __________ mA.

  4. A slanted object AB is placed on one side of convex lens as shown in the diagram. The image is formed on the opposite side. Angle made by the image with principal axis is :


  5. A spherical surface separates two media of refractive indices 1 and 1.5 as shown in figure. Distance of the image of an object 'O', is : 
    (C is the center of curvature of the spherical surface and R is the radius of curvature)

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