In the figure shown below, a resistance of $150.4 \Omega$ is connected in series to an ammeter A of resistance $240 \Omega$. A shunt resistance of $10 \Omega$ is connected in parallel with the ammeter. The reading of the ammeter is __________ mA.
To determine the reading of the ammeter, we first need to calculate the equivalent resistance of the circuit. The ammeter has an internal resistance of \(240 \, \Omega\) with a shunt resistance of \(10 \, \Omega\) in parallel. The equivalent resistance \(R_{\text{eq}}\) of these two resistances is given by:
\( \frac{1}{R_{\text{eq}}} = \frac{1}{240} + \frac{1}{10} \)
\( \frac{1}{R_{\text{eq}}} = \frac{1}{240} + \frac{24}{240} = \frac{25}{240} \)
\( R_{\text{eq}} = \frac{240}{25} = 9.6 \, \Omega \)
The total resistance in the circuit is the sum of the series resistance \(150.4 \, \Omega\) and the equivalent resistance of \(9.6 \, \Omega\):
\( R_{\text{total}} = 150.4 + 9.6 = 160 \, \Omega \)
Using Ohm’s law, the total current \(I\) through the circuit can be calculated using the voltage \(V = 20 \, V\):
\( I = \frac{V}{R_{\text{total}}} = \frac{20}{160} = 0.125 \, \text{A} \, (or \, 125 \, \text{mA}) \)
The current through the ammeter is the current through the shunt resistance, given by:
\( I_{\text{shunt}} = \frac{10}{10 + 240} \times 125 = \frac{10}{250} \times 125 = 5 \, \text{mA} \)
The reading of the ammeter is \(5 \, \text{mA}\), which falls within the expected range of 5 to 5 mA.
Consider following statements for refraction of light through prism, when angle of deviation is minimum.
A. The refracted ray inside prism becomes parallel to the base.
B. Larger angle prisms provide smaller angle of minimum deviation.
C. Angle of incidence and angle of emergence becomes equal.
D. There are always two sets of angle of incidence for which deviation will be same except at minimum deviation setting.
E. Angle of refraction becomes double of prism angle. Choose the correct answer from the options given below:
The radii of curvature for a thin convex lens are $10 \ cm$ and $15 \ cm$ respectively. The focal length of the lens is $12 \ cm$. The refractive index of the lens material is
The work function of a metal is $3 \ eV$. The color of the visible light that is required to cause emission of photoelectrons is
A slanted object AB is placed on one side of convex lens as shown in the diagram. The image is formed on the opposite side. Angle made by the image with principal axis is :

A spherical surface separates two media of refractive indices 1 and 1.5 as shown in figure. Distance of the image of an object 'O', is :
(C is the center of curvature of the spherical surface and R is the radius of curvature)
Consider following statements for refraction of light through prism, when angle of deviation is minimum.
A. The refracted ray inside prism becomes parallel to the base.
B. Larger angle prisms provide smaller angle of minimum deviation.
C. Angle of incidence and angle of emergence becomes equal.
D. There are always two sets of angle of incidence for which deviation will be same except at minimum deviation setting.
E. Angle of refraction becomes double of prism angle. Choose the correct answer from the options given below:
The radii of curvature for a thin convex lens are $10 \ cm$ and $15 \ cm$ respectively. The focal length of the lens is $12 \ cm$. The refractive index of the lens material is
The work function of a metal is $3 \ eV$. The color of the visible light that is required to cause emission of photoelectrons is
A slanted object AB is placed on one side of convex lens as shown in the diagram. The image is formed on the opposite side. Angle made by the image with principal axis is :

A spherical surface separates two media of refractive indices 1 and 1.5 as shown in figure. Distance of the image of an object 'O', is :
(C is the center of curvature of the spherical surface and R is the radius of curvature)