The volume of a solid hemisphere is \(\frac{396}{7} cm^3\). Find the total surface area of hemisphere
\(84.85\ cm^2\)
Volume of a hemisphere \(= \frac{2}{3}\pi r^3\).
\(\frac{2}{3} \times \frac{22}{7} \times r^3 = \frac{396}{7} \Rightarrow r^3 = \frac{396 \times 3}{2 \times 22} = 27 \Rightarrow r = 3\) cm.
Total surface area of a solid hemisphere \(= 3\pi r^2\).
\(3 \times \frac{22}{7} \times 9 = \frac{594}{7} \approx 84.85\ cm^2\)
Hence, the total surface area of the hemisphere is 84.85 cm2.
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Important Questions from 3-D Mensuration
- The curved surface area of a cylinder is half of its total surface area. If its height is 195 cm, then find its diameter (in cm).
The diameter of the base and slant height of a right circular cone are 30 cm and 113 cm, respectively. Find the volume (in cm³) of the given cone.
(Use $\pi = \frac{22}{7}$)- A cylindrical rod has an curved surface area of $4,900 \text{ cm}^2$. If the length of the rod is 97 cm, then the radius (in cm) of the rod, correct to two places of decimal, is:
Take $\pi = \frac{22}{7}$ - The volume (in $m^3$) of a cube, each of whose edges is 42 m, is:
The length and breadth of a cuboid are 50 cm and 75 cm, respectively. If the length of the diagonal is $17\sqrt{29}$ cm, then what is the volume (in $cm^{3}$) of the cuboid?
