The volume of a right circular cone, whose radius of the base is same as one-third of its altitude, and the volume of a sphere are equal. The ratio of the radius of the cone to the radius of the sphere is:
∛4 : ∛3
This problem involves a right circular cone and a sphere with equal volumes. We are given a relationship between the radius and altitude (height) of the cone and asked to find the ratio of the cone's radius to the sphere's radius.
First, let's write down the formulas for the volume of a cone and a sphere:
The problem states that the radius of the base of the cone is the same as one-third of its altitude. We can write this relation as:
\(r_c = \frac{1}{3} h_c\)
From this, we can express the altitude of the cone in terms of its radius:
\(h_c = 3r_c\)
The problem also states that the volume of the cone and the volume of the sphere are equal:
\(V_{cone} = V_{sphere}\)
Substitute the volume formulas into this equation:
\(\frac{1}{3} \pi r_c^2 h_c = \frac{4}{3} \pi r_s^3\)
Now, substitute the expression for \(h_c\) (\(h_c = 3r_c\)) into the volume equation:
\(\frac{1}{3} \pi r_c^2 (3r_c) = \frac{4}{3} \pi r_s^3\)
Let's simplify the left side of the equation:
\(\frac{1}{3} \pi r_c^2 (3r_c) = \pi r_c^3\)
So the equation becomes:
\(\pi r_c^3 = \frac{4}{3} \pi r_s^3\)
We want to find the ratio of the radius of the cone to the radius of the sphere, which is \(\frac{r_c}{r_s}\). Let's rearrange the equation to isolate the terms involving \(r_c\) and \(r_s\):
Divide both sides by \(\pi\) (since \(\pi \neq 0\)):
\(r_c^3 = \frac{4}{3} r_s^3\)
Divide both sides by \(r_s^3\) (assuming \(r_s \neq 0\)):
\(\frac{r_c^3}{r_s^3} = \frac{4}{3}\)
This can be written as:
\(\left(\frac{r_c}{r_s}\right)^3 = \frac{4}{3}\)
To find \(\frac{r_c}{r_s}\), take the cube root of both sides:
\(\frac{r_c}{r_s} = \sqrt[3]{\frac{4}{3}}\)
\(\frac{r_c}{r_s} = \frac{\sqrt[3]{4}}{\sqrt[3]{3}}\)
So, the ratio of the radius of the cone to the radius of the sphere is \(\sqrt[3]{4} : \sqrt[3]{3}\).
Based on the calculations, the ratio of the radius of the cone to the radius of the sphere is \(\sqrt[3]{4} : \sqrt[3]{3}\).
| Description | Formula/Relation |
|---|---|
| Volume of Cone | \(V_{cone} = \frac{1}{3} \pi r_c^2 h_c\) |
| Volume of Sphere | \(V_{sphere} = \frac{4}{3} \pi r_s^3\) |
| Cone Radius & Altitude Relation | \(r_c = \frac{1}{3} h_c\) or \(h_c = 3r_c\) |
| Equal Volumes | \(V_{cone} = V_{sphere}\) |
| Derived Ratio | \(r_c : r_s = \sqrt[3]{4} : \sqrt[3]{3}\) |
| Shape | Formula | Variables |
|---|---|---|
| Cube | \(V = s^3\) | \(s\): side length |
| Cuboid | \(V = l \times w \times h\) | \(l\): length, \(w\): width, \(h\): height |
| Cylinder | \(V = \pi r^2 h\) | \(r\): radius, \(h\): height |
| Cone | \(V = \frac{1}{3} \pi r^2 h\) | \(r\): base radius, \(h\): height |
| Sphere | \(V = \frac{4}{3} \pi r^3\) | \(r\): radius |
| Pyramid | \(V = \frac{1}{3} \times \text{Base Area} \times h\) | \(h\): height |
Let's look a bit deeper into the shapes involved in this problem: the cone and the sphere.
Understanding the basic properties and volume formulas for these shapes is crucial for solving geometry problems like this one, especially those involving equal volumes or surface areas.
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