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Question

The value of $x$ satisfying the equation $x^2 + a^2 = (b - x)^2$ is:

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
$\frac{b^2 - a^2}{2b}$

Solving the Equation $x^2 + a^2 = (b - x)^2$ for x

We need to find the value of $x$ that satisfies the given algebraic equation.

Step-by-Step Solution

  1. Start with the given equation:

    \(x^2 + a^2 = (b - x)^2\)

  2. Expand the term on the right side using the formula $(a - b)^2 = a^2 - 2ab + b^2$:

    \(x^2 + a^2 = b^2 - 2bx + x^2\)

  3. Simplify the equation by subtracting $x^2$ from both sides:

    \(a^2 = b^2 - 2bx\)

  4. Rearrange the equation to isolate the term containing $x$. Move $2bx$ to the left side and $a^2$ to the right side:

    \(2bx = b^2 - a^2\)

  5. Solve for $x$ by dividing both sides by $2b$. Assume $b \neq 0$.

    \(x = \frac{b^2 - a^2}{2b}\)

The value of $x$ satisfying the equation is $\frac{b^2 - a^2}{2b}$.

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