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Question

The value of $\frac{99}{100} \times 99$ is

The correct answer is
$98 \frac{1}{100}$

Evaluating the Expression $\frac{99}{100} \times 99$

This solution details the calculation steps to find the value of the mathematical expression $\frac{99}{100} \times 99$. The goal is to simplify the expression and present it as a mixed number.

Step-by-Step Calculation

  1. Start with the given expression:

    $ \frac{99}{100} \times 99 $

  2. Rewrite the fraction $\frac{99}{100}$ to make the calculation easier. Notice that $\frac{99}{100}$ is equal to $1 - \frac{1}{100}$.

    $ \left(1 - \frac{1}{100}\right) \times 99 $

  3. Distribute the $99$ to both terms inside the parentheses:

    $ (1 \times 99) - \left(\frac{1}{100} \times 99\right) $

  4. Simplify the terms:

    $ 99 - \frac{99}{100} $

  5. To subtract the fraction, express $99$ as an equivalent fraction with a denominator of $100$.

    $ 99 = \frac{99 \times 100}{100} = \frac{9900}{100} $

  6. Perform the subtraction:

    $ \frac{9900}{100} - \frac{99}{100} = \frac{9900 - 99}{100} $

  7. Calculate the numerator:

    $ 9900 - 99 = 9801 $

    The result is the improper fraction $\frac{9801}{100}$.

  8. Convert the improper fraction $\frac{9801}{100}$ to a mixed number. Divide $9801$ by $100$.

    $9801 \div 100 = 98$ with a remainder of $1$.

    Therefore, the mixed number is $98 \frac{1}{100}$.

Final Answer Value

The value of $\frac{99}{100} \times 99$ is $98 \frac{1}{100}$.

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Important Questions from Simplification

  1. Simplify: \((x^{\frac{m}{n}})^{m+n} \times (x^{\frac{n}{p}})^{n+p} \times (x^{p} \times x^{m})^{p-m}\)

  2. Simplify: 2×[4−{2−(2−3)−(2+3)}−1]−5×[−3−(3−2)]

  3. Simplify √81 + ³√64 —————————— ³√3³ + 4² + ³√216

  4. The value of 0.18÷0.015 is:

  5. The mean of scores obtained by 50 students is found to be 79.5. Later on, it was found that the score of one student was read as 94 in place of 49 and the score of another student was read as 69 in place of 89. Find the correct mean.

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