The mean of scores obtained by 50 students is found to be 79.5. Later on, it was found that the score of one student was read as 94 in place of 49 and the score of another student was read as 69 in place of 89. Find the correct mean.
79
This problem involves calculating the correct mean of a set of student scores after identifying errors in the initial data entry. The mean is a fundamental statistical measure that represents the average value of a dataset. When data points are recorded incorrectly, the calculated mean will also be incorrect. To find the correct mean, we must first determine the correct sum of the scores and then divide by the total number of students.
The mean (or average) of a dataset is calculated by summing all the values in the dataset and dividing by the number of values. The formula for the mean ($\bar{x}$) is:
$\bar{x} = \frac{\sum x}{n}$
Where:
In this problem, the 'values' are the scores obtained by the students.
We are given the following information:
The incorrect sum of scores can be found by rearranging the mean formula:
Incorrect Sum = Incorrect Mean $\times$ Number of students
Incorrect Sum = $79.5 \times 50$
Let's calculate this:
Incorrect Sum = $79.5 \times 50 = 3975$
So, the sum of the scores as initially calculated with the errors was 3975.
We are told that two scores were read incorrectly:
To find the correct sum, we need to remove the incorrect scores from the incorrect sum and add the correct scores.
Incorrect scores that were included in the sum: 94 and 69.
Correct scores that should have been included: 49 and 89.
Total value of incorrect scores included = $94 + 69 = 163$
Total value of correct scores that should be included = $49 + 89 = 138$
The adjustment needed for the sum is: (Sum of correct scores) - (Sum of incorrect scores)
Adjustment = $138 - 163 = -25$
Now, we can find the correct sum of scores:
Correct Sum = Incorrect Sum + Adjustment
Correct Sum = $3975 + (-25)$
Correct Sum = $3975 - 25 = 3950$
The correct sum of the scores is 3950.
Now that we have the correct sum of scores and the number of students, we can calculate the correct mean using the mean formula:
Correct Mean = $\frac{\text{Correct Sum}}{\text{Number of students}}$
Correct Mean = $\frac{3950}{50}$
Let's calculate this:
Correct Mean = $\frac{3950}{50} = \frac{395}{5}$
Correct Mean = 79
The correct mean of the scores obtained by the 50 students is 79.
| Concept | Definition | Formula/Use |
|---|---|---|
| Mean | The average of a set of numbers. | $\bar{x} = \frac{\sum x}{n}$ |
| Sum of Scores | The total obtained by adding all individual scores. | $\sum x = \text{Mean} \times n$ |
| Data Correction | The process of adjusting data for errors or inconsistencies. | Involves removing incorrect entries and adding correct ones to sums/totals. |
Errors in data collection or entry are common in statistics. Recognizing and correcting these errors is crucial for obtaining accurate results and making reliable conclusions. Common types of errors include:
When dealing with incorrect entries in sum-based statistics like the mean, the method used in this problem (subtracting the wrong values and adding the correct values to the total sum) is the standard approach. For other statistics like variance or standard deviation, correcting the data and recalculating is necessary.
Ensuring data accuracy is a critical step before performing any statistical analysis to ensure the validity of the findings.
The value of 0.18÷0.015 is:
Simplify √81 + ³√64 —————————— ³√3³ + 4² + ³√216
Simplify: 2×[4−{2−(2−3)−(2+3)}−1]−5×[−3−(3−2)]
Simplify: \((x^{\frac{m}{n}})^{m+n} \times (x^{\frac{n}{p}})^{n+p} \times (x^{p} \times x^{m})^{p-m}\)
Which of the following is correct for divisibility?
(A) A number is divisible by 6 if it is divisible by 3 or 2.
(B) A number is divisible by 5 if its unit digit is 0 or 5.
(C) A number is divisible by 3 if its unit digit is divisible by 3.
(D) A number is divisible by 4 if the number formed by its last two digits is divisible by 4.
Choose the correct answer from the options given below: