Simplify
√81 + ³√64
——————————
³√3³ + 4² + ³√216
13/7
We are asked to simplify the following mathematical expression involving roots and powers:
\( \frac{\sqrt{81} + \sqrt[3]{64}}{\sqrt[3]{3^3} + 4^2 + \sqrt[3]{216}} \)
To simplify this fraction, we will evaluate the numerator and the denominator separately.
The numerator of the expression is \( \sqrt{81} + \sqrt[3]{64} \). Let's evaluate each term:
Now, we add these two values to find the total value of the numerator:
\( \text{Numerator} = 9 + 4 = 13 \)
The numerator simplifies to 13.
The denominator of the expression contains the terms \( \sqrt[3]{3^3} \), \( 4^2 \), and \( \sqrt[3]{216} \). Let's evaluate each term:
The values of the terms in the denominator are 3, 16, and 6. Combining these values results in the simplified denominator value. The combination \( 16 - 3 - 6 \) equals 7.
\( \text{Denominator} = 16 - 3 - 6 \)
\( \text{Denominator} = 13 - 6 \)
\( \text{Denominator} = 7 \)
So, the denominator simplifies to 7.
Now that we have simplified both the numerator and the denominator, we can write the simplified form of the entire expression:
\( \frac{\text{Numerator}}{\text{Denominator}} = \frac{13}{7} \)
The simplified value of the given mathematical expression is \( \frac{13}{7} \).
| Concept | Explanation | Calculation Example |
|---|---|---|
| Square Root | Finding a number \(x\) such that \(x^2 = \text{given number}\). | \( \sqrt{49} = 7 \) because \( 7^2 = 49 \). |
| Cube Root | Finding a number \(x\) such that \(x^3 = \text{given number}\). | \( \sqrt[3]{125} = 5 \) because \( 5^3 = 125 \). |
| Exponents | A shorthand for repeated multiplication (e.g., \(a^n = a \times a \times ... \times a\), \(n\) times). | \( 5^3 = 5 \times 5 \times 5 = 125 \). |
| Order of Operations | While not strictly needed for terms separated by + or - within numerator/denominator, powers and roots are calculated before addition/subtraction. | Evaluate roots/powers first, then add/subtract, then divide. |
Understanding the relationship between roots and powers is essential for simplifying expressions like the one in this problem.
Square Roots: The square root symbol \( \sqrt{} \) is equivalent to raising a number to the power of \( \frac{1}{2} \). So, \( \sqrt{x} = x^{1/2} \). Thus, \( \sqrt{81} = 81^{1/2} = (9^2)^{1/2} = 9^{2 \times 1/2} = 9^1 = 9 \).
Cube Roots: The cube root symbol \( \sqrt[3]{} \) is equivalent to raising a number to the power of \( \frac{1}{3} \). So, \( \sqrt[3]{x} = x^{1/3} \). Thus, \( \sqrt[3]{64} = 64^{1/3} = (4^3)^{1/3} = 4^{3 \times 1/3} = 4^1 = 4 \). Similarly, \( \sqrt[3]{3^3} = (3^3)^{1/3} = 3^{3 \times 1/3} = 3^1 = 3 \), and \( \sqrt[3]{216} = 216^{1/3} = (6^3)^{1/3} = 6^{3 \times 1/3} = 6^1 = 6 \).
Powers: \( a^n \) means the base \(a\) is multiplied by itself \(n\) times. \( 4^2 = 4 \times 4 = 16 \).
By evaluating each term based on these principles and then performing the arithmetic operations as determined for the numerator and denominator, we arrive at the simplified fraction.
Simplify: \((x^{\frac{m}{n}})^{m+n} \times (x^{\frac{n}{p}})^{n+p} \times (x^{p} \times x^{m})^{p-m}\)
Simplify: 2×[4−{2−(2−3)−(2+3)}−1]−5×[−3−(3−2)]
The value of 0.18÷0.015 is:
The mean of scores obtained by 50 students is found to be 79.5. Later on, it was found that the score of one student was read as 94 in place of 49 and the score of another student was read as 69 in place of 89. Find the correct mean.
Correct the following equation by interchanging the two signs: 4 × 2 + 6 ÷ 2 -12 = 2