To find the value of $27^3 - 22^3$, we can use the algebraic identity for the difference of cubes: $a^3 - b^3 = (a - b)(a^2 + ab + b^2)$
Identify $a$ and $b$:
Calculate the difference $(a - b)$:
$27 - 22 = 5$
Calculate the terms $a^2$, $ab$, and $b^2$:
Calculate the sum $(a^2 + ab + b^2)$:
$729 + 594 + 484 = 1807$
Multiply the results from step 2 and step 4:
$5 \times 1807 = 9035$
Alternatively, calculate the cubes directly:
Therefore, the value of $27^3 - 22^3$ is $9035$.
Identify the number that will replace the question mark in the second equation based on the relationship represented in the first equation.

Simplify: $\frac{\sqrt{16x^4 - 72x^2y^2 + 81y^4}}{\sqrt{4x^2 - 12xy + 9y^2}} - (2x - 3y)$, given that $2x > 3y$.