To find the value of $27^3 - 22^3$, we can use the algebraic identity for the difference of cubes: $a^3 - b^3 = (a - b)(a^2 + ab + b^2)$
Identify $a$ and $b$:
Calculate the difference $(a - b)$:
$27 - 22 = 5$
Calculate the terms $a^2$, $ab$, and $b^2$:
Calculate the sum $(a^2 + ab + b^2)$:
$729 + 594 + 484 = 1807$
Multiply the results from step 2 and step 4:
$5 \times 1807 = 9035$
Alternatively, calculate the cubes directly:
Therefore, the value of $27^3 - 22^3$ is $9035$.
$ \sqrt[3]{0.99}$ is closest to
$\frac{ ( 20^{2} - 10^{2} ) +5 \times 3 +10 } { \frac{1}{3} \text{of} 27 + 10 + 2 + 1 } =?$