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Question

$\frac{\sqrt[3]{6859}}{\sqrt[4]{256}} \times \frac{2}{57} \times 168 = ?$

The correct answer is
28

Simplifying the Radical Expression

The problem asks to evaluate the expression: $ \frac{\sqrt[3]{6859}}{\sqrt[4]{256}} \times \frac{2}{57} \times 168 $ To solve this, we first find the values of the cube root and the fourth root.

Calculating Roots

  • Cube Root Calculation: We need to find a number whose cube is 6859. Testing integer values, we find that $19^3 = 19 \times 19 \times 19 = 6859$. Therefore, $\sqrt[3]{6859} = 19$.
  • Fourth Root Calculation: We need to find a number whose fourth power is 256. We know that $4^4 = 4 \times 4 \times 4 \times 4 = 256$. Therefore, $\sqrt[4]{256} = 4$.

Substituting and Simplifying

Substitute the calculated root values back into the expression:

$ \frac{19}{4} \times \frac{2}{57} \times 168 $

Now, simplify the expression step-by-step:

  1. Combine fractions: Notice that $57 = 19 \times 3$. Simplify the first two terms: $ \frac{19}{4} \times \frac{2}{57} = \frac{19}{4} \times \frac{2}{19 \times 3} $ Cancel out the common factor 19: $ \frac{1}{4} \times \frac{2}{3} = \frac{2}{12} = \frac{1}{6} $
  2. Multiply by the remaining term: Now multiply the result by 168: $ \frac{1}{6} \times 168 $ Perform the division: $ \frac{168}{6} = 28 $

The value of the expression is 28.

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Important Questions from Simplification (Notes)

  1. The value of $(-27) \times (-16) + (-27) \times (-14)$ is

  2. Evaluate: (-9) - (-56) ÷ (-14) + (-4) × 7
  3. In the Delhi zoo, there are some ducks and rabbits. If the heads are counted there are 160, while the legs are 450. What will be number of ducks in the zoo ?
  4. Identify the number that will replace the question mark in the second equation based on the relationship represented in the first equation.

     

  5. Simplify $(5z-12y)^2 + (12z+5y)^2 - 144z^2$.
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