The total number of valence electrons in $W(\eta^3-Cp)(\eta^5-Cp)(CO)_2$ is ______________.(Atomic number of W = 74)
This solution determines the total number of valence electrons for the given Tungsten (W) complex using the electron counting method.
Tungsten (W) is a Group 6 transition metal.
The complex contains three types of ligands:
The total number of valence electrons is the sum of the valence electrons from the metal center and all the ligands.
Total Valence Electrons = (Valence e⁻ of W) + (e⁻ from $\eta^3$-Cp) + (e⁻ from $\eta^5$-Cp) + (e⁻ from 2 CO)
Calculation: $6 + 3 + 5 + (2 \times 2)$
Total Valence Electrons = $6 + 3 + 5 + 4 = 18$
The total number of valence electrons in the $W(\eta^3-Cp)(\eta^5-Cp)(CO)_2$ complex is 18.
The given zirconocene compound, $(\eta^5-\text{Cp})_2\text{ZrEt}_2$, when heated in the presence of an equimolar amount of $\text{PMe}_3$ results in the formation of a compound $X$ which obeys the 18 electron rule. The reaction also resulted in the release of a saturated hydrocarbon.
[Given: Atomic number of $\text{Zr} = 40$]
The structure of compound $X$ is ________
The number of metal-metal bond(s) in the complex $[(\eta^5-Cp)Mo(CO)_2]_2$ is $x$ and in $[(\eta^5-Cp)_2Fe_2(CO)_3]$ is $y$. The value of $x + y$ is ___________.
(Assume 18 electron rule is followed.)
(Answer in integer)
$[CpMoCl_2]_2$ obeys the 18 electron rule. The correct structure of this compound is
(atomic number of Mo = 42)