Directions: Study the data in the given table and answer the questions that follow The table below embodies data on the number of students who appeared (A) and passed (P) in a competitive examination from four different zones (K, L, M and N) during the year 2014 to 2019. Year ↓ Zone → K L M N A P A P A P A P 2014 782 360 612 310 720 410 1020 802 2015 804 472 608 324 728 480 1135 840 2016 720 448 636 298 680 390 1084 864 2017 750 360 655 305 695 396 1096 766 2018 824 504 640 346 712 424 1180 752 2019 850 496 600 315 740 464 1165 780
The total number of students who passed from Zone-M in all the six years taken together is approximately what percentage of the total number of students who appeared from Zone-M in all the six years taken together?
60%
Used Formula:
Pass percentage of students = Passed students/Present students × 100
Calculation:
Total number of passed students in Zone-M over all six years = 410 + 480 + 390 + 396 + 424 + 464 = 2564
Total number of present students in Zone-M over all six years = 720 + 728 + 680 + 695 + 712 + 740 = 4275
Percentage = 2564/4275 × 100 = 59.98% ≈ 60%
∴ Desired percentage is 60%
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