The question asks for the specific temperature at which a liquid, when in an open container, reaches a state where its internal vapour pressure is exactly the same as the pressure of the surrounding atmosphere. Let's explore this concept:
All liquids have a tendency to evaporate, meaning some molecules escape from the liquid surface and become gas (vapour). In a closed container, these vapour molecules eventually build up enough pressure to counteract further evaporation, reaching a state called equilibrium. This pressure exerted by the vapour in equilibrium with its liquid phase at a given temperature is known as the vapour pressure.
The atmospheric pressure is the force exerted by the weight of the air in the atmosphere above a certain point. This pressure varies with altitude and weather conditions.
The boiling point is defined as the temperature at which the vapour pressure of a liquid equals the surrounding atmospheric pressure.
For example, water boils at 100°C (212°F) at standard atmospheric pressure. If the atmospheric pressure is lower (like at higher altitudes), the boiling point is lower. If the atmospheric pressure is higher (like in a pressure cooker), the boiling point is higher.
Therefore, the temperature at which the vapour pressure of a liquid in an open vessel becomes equal to the atmospheric pressure is called the boiling point.
Which one of the following is also known as Dry ice in its solid form?
Which of the following is not a characteristic of 'solid'?
Which among the following is NOT an example of matter?
Identify the element that is NOT a metalloid.
What is called conversion from a liquid state to a gaseous state?
A. Oxidization
B. Sublimation
C. Evaporation
D. Condensation
The gases obtained on heating FeSO4 are-