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Question

The table given below shows the production of bike by two companies in 6 years.

YearsAB
P300550
Q150400
R250300
S500100
T35050
U200150

J1 = The value of average production of bike by A in year P, Q, R and S.

J2 = The value of average production of bike by B in year T and U.

What is the value of (J1/J2)? 

The correct answer is

3

Analyzing Bike Production Data

The question asks us to analyze the bike production data provided in a table for two companies, A and B, over six years (P, Q, R, S, T, U). We need to calculate two values, J1 and J2, based on this data and then find the ratio (J1/J2).

Years A B
P 300 550
Q 150 400
R 250 300
S 500 100
T 350 50
U 200 150

Let's first understand what J1 and J2 represent:

  • J1 is the average production of bikes by company A in years P, Q, R, and S.
  • J2 is the average production of bikes by company B in years T and U.

Calculating J1: Average Production for Company A

To find the average production of company A in years P, Q, R, and S, we need to sum the production values for company A in these specific years and divide by the number of years involved.

  • Production by A in Year P = 300
  • Production by A in Year Q = 150
  • Production by A in Year R = 250
  • Production by A in Year S = 500

Sum of production by A in years P, Q, R, S:

\( \text{Sum} = 300 + 150 + 250 + 500 = 1200 \)

Number of years = 4 (P, Q, R, S)

Now, calculate J1:

\( \text{J1} = \frac{\text{Sum}}{\text{Number of years}} = \frac{1200}{4} = 300 \)

So, the value of J1 is 300.

Calculating J2: Average Production for Company B

Next, we need to find the average production of company B in years T and U. We sum the production values for company B in these years and divide by the number of years.

  • Production by B in Year T = 50
  • Production by B in Year U = 150

Sum of production by B in years T, U:

\( \text{Sum} = 50 + 150 = 200 \)

Number of years = 2 (T, U)

Now, calculate J2:

\( \text{J2} = \frac{\text{Sum}}{\text{Number of years}} = \frac{200}{2} = 100 \)

So, the value of J2 is 100.

Final Calculation: J1 divided by J2

The question asks for the value of (J1/J2).

\( \frac{\text{J1}}{\text{J2}} = \frac{300}{100} \)

\( \frac{\text{J1}}{\text{J2}} = 3 \)

The value of (J1/J2) is 3.

Understanding Average in Data Analysis

The average (or mean) is a common measure used in data analysis. It gives us a central value for a set of numbers. Calculating the average helps in summarizing data and making comparisons. In this problem, calculating the average bike production allows us to represent the typical production level for a specific company over certain periods.

Revision Table: Key Values

Metric Calculation Value
Sum of A's Production (P, Q, R, S) 300 + 150 + 250 + 500 1200
J1 (Average A Production P, Q, R, S) 1200 / 4 300
Sum of B's Production (T, U) 50 + 150 200
J2 (Average B Production T, U) 200 / 2 100
Ratio (J1/J2) 300 / 100 3

Additional Information on Data Interpretation

Data interpretation questions like this one test your ability to extract information from tables, graphs, or charts and use it to perform calculations or answer specific questions. Key skills required include careful reading of the question, accurate data extraction, and correct application of mathematical concepts such as averages and ratios. Practicing different types of data representation (tables, bar graphs, pie charts, line graphs) and various calculations (percentage, ratio, average, change) is crucial for mastering data interpretation.

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Important Questions from Tabulation

  1. Table shows income (in Rs.) received by 4 employees of a company during the month of December 2020 and all their income sources.

    Source

    Amit

    Suresh

    Nitin

    Varun

    Salary

    35000

    38000

    29000

    42000

    Arrears

    6000

    6300

    5000

    7500

    Bonus

    1000

    1100

    1000

    1240

    Overtime

    1800

    1950

    1400

    1500


    By what percent are the Arrears of Amit and Suresh taken together less than the Arrears of Nitin and Varun taken together?
  2. The table given below shows the GDP of two countries in different five years.

    Country
    YearsAB
    Y1175285
    Y2200300
    Y3150125
    Y47585
    Y55095

    K1 = The value of average GDP of country A in all the 5 years.

    K2 = The value of average GDP of country B in all the 5 years.

    What is the value of (K1 + K2)?

  3. Study the Table Properly and answer by interpreting the data

    The table shows the percentage population of five districts in a state below poverty line and the proportion of males and females.

    DistrictPercentage of population
    below poverty level
    Proportion of Male and Female 
    Below poverty line (M:F)Above poverty Line (M:F)
    D1152 : 33 : 2
    D2183 : 47 : 5
    D3202 : 53 : 4
    D4255 : 24 : 3
    D5123 : 72 : 7

    If the total population in the district D3 is 40,000, then what is the population of below poverty line in the district D3, ?

  4. The table given below shows the marks obtained by 4 students in 5 subjects. The maximum marks of each subject is 100.

    Subjects

    Students

    P1

    P2

    P3

    P4

    S1

    89

    100

    92

    91

    S2

    62

    52

    72

    37

    S3

    57

    55

    70

    65

    S4

    76

    85

    76

    58

    S5

    85

    70

    66

    62

    What is the total percent marks of P4?

  5. The data given below shows the number of people who have saved a certain amount of money.

    Savings

    (in Rs.)

    Number of people

    5

    1

    15

    3

    20

    4

    25

    2

    30

    1

    35

    1

    40

    2

    What is the mode of the given data?

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