The table given below shows the production of bike by two companies in 6 years. J1 = The value of average production of bike by A in year P, Q, R and S. J2 = The value of average production of bike by B in year T and U. What is the value of (J1/J2)? Years A B P 300 550 Q 150 400 R 250 300 S 500 100 T 350 50 U 200 150
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The question asks us to analyze the bike production data provided in a table for two companies, A and B, over six years (P, Q, R, S, T, U). We need to calculate two values, J1 and J2, based on this data and then find the ratio (J1/J2).
| Years | A | B |
|---|---|---|
| P | 300 | 550 |
| Q | 150 | 400 |
| R | 250 | 300 |
| S | 500 | 100 |
| T | 350 | 50 |
| U | 200 | 150 |
Let's first understand what J1 and J2 represent:
To find the average production of company A in years P, Q, R, and S, we need to sum the production values for company A in these specific years and divide by the number of years involved.
Sum of production by A in years P, Q, R, S:
\( \text{Sum} = 300 + 150 + 250 + 500 = 1200 \)
Number of years = 4 (P, Q, R, S)
Now, calculate J1:
\( \text{J1} = \frac{\text{Sum}}{\text{Number of years}} = \frac{1200}{4} = 300 \)
So, the value of J1 is 300.
Next, we need to find the average production of company B in years T and U. We sum the production values for company B in these years and divide by the number of years.
Sum of production by B in years T, U:
\( \text{Sum} = 50 + 150 = 200 \)
Number of years = 2 (T, U)
Now, calculate J2:
\( \text{J2} = \frac{\text{Sum}}{\text{Number of years}} = \frac{200}{2} = 100 \)
So, the value of J2 is 100.
The question asks for the value of (J1/J2).
\( \frac{\text{J1}}{\text{J2}} = \frac{300}{100} \)
\( \frac{\text{J1}}{\text{J2}} = 3 \)
The value of (J1/J2) is 3.
The average (or mean) is a common measure used in data analysis. It gives us a central value for a set of numbers. Calculating the average helps in summarizing data and making comparisons. In this problem, calculating the average bike production allows us to represent the typical production level for a specific company over certain periods.
| Metric | Calculation | Value |
|---|---|---|
| Sum of A's Production (P, Q, R, S) | 300 + 150 + 250 + 500 | 1200 |
| J1 (Average A Production P, Q, R, S) | 1200 / 4 | 300 |
| Sum of B's Production (T, U) | 50 + 150 | 200 |
| J2 (Average B Production T, U) | 200 / 2 | 100 |
| Ratio (J1/J2) | 300 / 100 | 3 |
Data interpretation questions like this one test your ability to extract information from tables, graphs, or charts and use it to perform calculations or answer specific questions. Key skills required include careful reading of the question, accurate data extraction, and correct application of mathematical concepts such as averages and ratios. Practicing different types of data representation (tables, bar graphs, pie charts, line graphs) and various calculations (percentage, ratio, average, change) is crucial for mastering data interpretation.
Table shows income (in Rs.) received by 4 employees of a company during the month of December 2020 and all their income sources.
Source | Amit | Suresh | Nitin | Varun |
Salary | 35000 | 38000 | 29000 | 42000 |
Arrears | 6000 | 6300 | 5000 | 7500 |
Bonus | 1000 | 1100 | 1000 | 1240 |
Overtime | 1800 | 1950 | 1400 | 1500 |
The table given below shows the GDP of two countries in different five years.
| Country | ||
| Years | A | B |
| Y1 | 175 | 285 |
| Y2 | 200 | 300 |
| Y3 | 150 | 125 |
| Y4 | 75 | 85 |
| Y5 | 50 | 95 |
K1 = The value of average GDP of country A in all the 5 years.
K2 = The value of average GDP of country B in all the 5 years.
What is the value of (K1 + K2)?
Study the Table Properly and answer by interpreting the data
The table shows the percentage population of five districts in a state below poverty line and the proportion of males and females.
| District | Percentage of population below poverty level | Proportion of Male and Female | |
| Below poverty line (M:F) | Above poverty Line (M:F) | ||
| D1 | 15 | 2 : 3 | 3 : 2 |
| D2 | 18 | 3 : 4 | 7 : 5 |
| D3 | 20 | 2 : 5 | 3 : 4 |
| D4 | 25 | 5 : 2 | 4 : 3 |
| D5 | 12 | 3 : 7 | 2 : 7 |
If the total population in the district D3 is 40,000, then what is the population of below poverty line in the district D3, ?
The table given below shows the marks obtained by 4 students in 5 subjects. The maximum marks of each subject is 100.
Subjects | Students | |||
P1 | P2 | P3 | P4 | |
S1 | 89 | 100 | 92 | 91 |
S2 | 62 | 52 | 72 | 37 |
S3 | 57 | 55 | 70 | 65 |
S4 | 76 | 85 | 76 | 58 |
S5 | 85 | 70 | 66 | 62 |
What is the total percent marks of P4?
The data given below shows the number of people who have saved a certain amount of money.
Savings (in Rs.) | Number of people |
5 | 1 |
15 | 3 |
20 | 4 |
25 | 2 |
30 | 1 |
35 | 1 |
40 | 2 |
What is the mode of the given data?