The table given below shows the production of bike and truck by five companies. A1 = The difference between the total production of bikes and trucks by all the 5 companies. A2 = The average production of bike by company D, F and H. What is the value of (A2/A1)?Production Companies Bike Truck D 700 500 E 450 300 F 500 200 G 250 600 H 300 650
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This question asks us to analyze data from a table showing the production of bikes and trucks by five different companies. We need to calculate two specific values, A1 and A2, based on the data and then find the ratio A2/A1.
| Companies | Bike Production | Truck Production |
|---|---|---|
| D | 700 | 500 |
| E | 450 | 300 |
| F | 500 | 200 |
| G | 250 | 600 |
| H | 300 | 650 |
A1 is defined as the difference between the total production of bikes and trucks by all five companies (D, E, F, G, H).
First, let's calculate the total bike production by all companies:
Total Bike Production = Production by D + Production by E + Production by F + Production by G + Production by H
Total Bike Production = \(700 + 450 + 500 + 250 + 300\)
Total Bike Production = \(2200\)
Next, let's calculate the total truck production by all companies:
Total Truck Production = Production by D + Production by E + Production by F + Production by G + Production by H
Total Truck Production = \(500 + 300 + 200 + 600 + 650\)
Total Truck Production = \(2250\)
Now, we find the difference between the total production of bikes and trucks:
A1 = |Total Bike Production - Total Truck Production|
A1 = \(|2200 - 2250|\)
A1 = \(|-50|\)
A1 = \(50\)
So, the value of A1 is 50.
A2 is defined as the average production of bikes by company D, company F, and company H.
Bike production for company D = 700
Bike production for company F = 500
Bike production for company H = 300
To find the average, we sum the bike production for these three companies and divide by 3:
A2 = (Bike Production by D + Bike Production by F + Bike Production by H) / 3
A2 = \((700 + 500 + 300) / 3\)
A2 = \(1500 / 3\)
A2 = \(500\)
So, the value of A2 is 500.
Finally, we need to find the value of the ratio (A2/A1).
We have A1 = 50 and A2 = 500.
Ratio = A2 / A1
Ratio = \(500 / 50\)
Ratio = \(10\)
The value of (A2/A1) is 10.
| Calculation | Description | Value |
|---|---|---|
| Total Bike Production | Sum of bike production across all companies | 2200 |
| Total Truck Production | Sum of truck production across all companies | 2250 |
| A1 | Difference between total bike and truck production | 50 |
| Bike Production (D, F, H) | Bike production by companies D, F, and H | 700, 500, 300 |
| A2 | Average bike production by D, F, and H | 500 |
| A2/A1 | Ratio of A2 to A1 | 10 |
This problem uses fundamental concepts in data analysis: calculating sums, differences, and averages from a dataset presented in a table. Understanding how to extract specific data points and perform calculations accurately is key to solving such problems.
Data interpretation questions often require combining these basic calculations based on the specific definitions provided for variables like A1 and A2.
Table shows income (in Rs.) received by 4 employees of a company during the month of December 2020 and all their income sources.
Source | Amit | Suresh | Nitin | Varun |
Salary | 35000 | 38000 | 29000 | 42000 |
Arrears | 6000 | 6300 | 5000 | 7500 |
Bonus | 1000 | 1100 | 1000 | 1240 |
Overtime | 1800 | 1950 | 1400 | 1500 |
The table given below shows the GDP of two countries in different five years.
| Country | ||
| Years | A | B |
| Y1 | 175 | 285 |
| Y2 | 200 | 300 |
| Y3 | 150 | 125 |
| Y4 | 75 | 85 |
| Y5 | 50 | 95 |
K1 = The value of average GDP of country A in all the 5 years.
K2 = The value of average GDP of country B in all the 5 years.
What is the value of (K1 + K2)?
Study the Table Properly and answer by interpreting the data
The table shows the percentage population of five districts in a state below poverty line and the proportion of males and females.
| District | Percentage of population below poverty level | Proportion of Male and Female | |
| Below poverty line (M:F) | Above poverty Line (M:F) | ||
| D1 | 15 | 2 : 3 | 3 : 2 |
| D2 | 18 | 3 : 4 | 7 : 5 |
| D3 | 20 | 2 : 5 | 3 : 4 |
| D4 | 25 | 5 : 2 | 4 : 3 |
| D5 | 12 | 3 : 7 | 2 : 7 |
If the total population in the district D3 is 40,000, then what is the population of below poverty line in the district D3, ?
The table given below shows the marks obtained by 4 students in 5 subjects. The maximum marks of each subject is 100.
Subjects | Students | |||
P1 | P2 | P3 | P4 | |
S1 | 89 | 100 | 92 | 91 |
S2 | 62 | 52 | 72 | 37 |
S3 | 57 | 55 | 70 | 65 |
S4 | 76 | 85 | 76 | 58 |
S5 | 85 | 70 | 66 | 62 |
What is the total percent marks of P4?
The data given below shows the number of people who have saved a certain amount of money.
Savings (in Rs.) | Number of people |
5 | 1 |
15 | 3 |
20 | 4 |
25 | 2 |
30 | 1 |
35 | 1 |
40 | 2 |
What is the mode of the given data?