To solve the problem, let's first define the variables for the present ages of Bunty and Bubbly. Let \(x\) be the present age of Bunty, and \(y\) be the present age of Bubbly.
According to the problem:
We now have two equations to work with:
Let's simplify Equation 2:
\(x + 2 = 3y + 6\)
Rearranging gives: \(x = 3y + 4\) (Equation 3)
Now, substitute Equation 3 into Equation 1:
\(3y + 4 + y = 64\)
Combine like terms:
\(4y + 4 = 64\)
Subtract 4 from both sides:
\(4y = 60\)
Divide by 4:
\(y = 15\)
Now that we have Bubbly's age, substitute \(y = 15\) back into Equation 1 to find Bunty's age:
\(x + 15 = 64\)
Subtract 15 from both sides:
\(x = 49\)
Thus, Bunty's present age is 49 years.
Therefore, the correct answer is 49.
The average age of a husband and his wife was 20 years at the time of their marriage. After 6 years, they have a 2 -year old child. Find the present average age of the family.
The ratio of the ages of A, B and C, 5 years ago, was 4 : 5 : 7. The sum of their present ages is 135 years. What will be the sum of the ages (in years) of B and C, 3 years from now?
The ratio of the present age of Mahesh and Ajay is 3 : 2 respectively. After 8 years. Ratio of their age will be 11: 8. What will be the present age of Mahesh’s son if his age is half of the present age of Ajay?
In a school, the average age of boys and girls together is 16.8 years, the average age of boys is 15.4 years, and the average age of girls is 18.2 years. The ratio of number of boys to girls in the school is:
The difference between age of Sunita and Sheela is 12 years. If 9 years ago, elder's age was 4 times of younger's age, then what are their present age?
A. 11 and 23
B. 15 and 27
C. 13 and 25
D. 23 and 35