The sum of the length and breadth of a cuboid is 16 cm. If the height of the cuboid is 1/4 of the sum of its length and breadth, then what is the lateral surface area of the cuboid?
128 cm2
Calculating the Lateral Surface Area of a Cuboid
Let the length, breadth, and height of the cuboid be $l$, $b$, and $h$ respectively.
Understanding the Given Information
We are given the following information about the cuboid:
- The sum of the length and breadth is 16 cm. This can be written as:
- $l + b = 16 \text{ cm}$
- The height of the cuboid is $\frac{1}{4}$ of the sum of its length and breadth. This can be written as:
- $h = \frac{1}{4} \times (l + b)$
Finding the Height of the Cuboid
We can substitute the given sum of length and breadth into the equation for the height:
$h = \frac{1}{4} \times (l + b)$
Since $l + b = 16 \text{ cm}$, we have:
$h = \frac{1}{4} \times 16 \text{ cm}$
Calculating the height:
$h = 4 \text{ cm}$
Calculating the Lateral Surface Area of the Cuboid
The lateral surface area (LSA) of a cuboid is the sum of the areas of its four side faces (excluding the top and bottom faces). The formula for the lateral surface area of a cuboid is:
$\text{LSA} = 2 \times \text{height} \times (\text{length} + \text{breadth})$
In terms of $l$, $b$, and $h$:
$\text{LSA} = 2h(l + b)$
We have already found that $h = 4 \text{ cm}$ and we are given that $l + b = 16 \text{ cm}$. Now, we substitute these values into the formula:
$\text{LSA} = 2 \times 4 \text{ cm} \times 16 \text{ cm}$
$\text{LSA} = 8 \text{ cm} \times 16 \text{ cm}$
$\text{LSA} = 128 \text{ cm}^2$
Therefore, the lateral surface area of the cuboid is 128 cm$^2$.
Summary of Calculations
| Parameter | Value/Relation | Calculated Value |
|---|---|---|
| Sum of Length and Breadth ($l+b$) | Given | 16 cm |
| Height ($h$) | $\frac{1}{4} \times (l+b)$ | $\frac{1}{4} \times 16 \text{ cm} = 4 \text{ cm}$ |
| Lateral Surface Area (LSA) | $2h(l+b)$ | $2 \times 4 \text{ cm} \times 16 \text{ cm} = 128 \text{ cm}^2$ |
Revision Table: Cuboid Formulas
| Concept | Formula | Description |
|---|---|---|
| Volume | $V = l \times b \times h$ | Space occupied by the cuboid |
| Total Surface Area (TSA) | $\text{TSA} = 2(lb + bh + hl)$ | Sum of the areas of all six faces |
| Lateral Surface Area (LSA) | $\text{LSA} = 2h(l + b)$ | Sum of the areas of the four side faces |
| Diagonal | $d = \sqrt{l^2 + b^2 + h^2}$ | Length of the longest segment connecting opposite vertices |
Additional Information: Understanding Surface Area
Surface area is a measure of the total area that the surface of a three-dimensional object occupies. For a cuboid, there are two main types of surface area often calculated: total surface area and lateral surface area.
- Total Surface Area: This includes the area of all six faces (top, bottom, front, back, left, right).
- Lateral Surface Area: This includes only the area of the four vertical faces (front, back, left, right). It is often referred to as the area of the walls if the base is the floor and the top is the ceiling.
In this problem, we specifically calculated the lateral surface area using the given dimensions.
Important Questions from Solid Figures
The area of the floor of a cubical room is 192 m 2. The length of the longest rod that can be kept in that room is :
A solid metallic rectangular block of dimensions 112 cm × 44 cm × 25 cm is melted and recast into a cylinder of radius 35 cm. The curved surface area (in cm 2) of the cylinder is: (Take π = 22/7)
If the volume of a cube is 175616 cm 3, what is its side?
The volume of a right circular cone is 1232 cm 3. If the height of the cone is 24 cm, then what will be the radius of its base?
A right triangle contains the right angle between the sides 5 cm and 7 cm. A cone is generated by revolving about the side 5 cm. The volume of this cone is:
