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Question

The sum of the length and breadth of a cuboid is 16 cm. If the height of the cuboid is 1/4 of the sum of its length and breadth, then what is the lateral surface area of the cuboid?

The correct answer is

128 cm2

Calculating the Lateral Surface Area of a Cuboid

Let the length, breadth, and height of the cuboid be $l$, $b$, and $h$ respectively.

Understanding the Given Information

We are given the following information about the cuboid:

  • The sum of the length and breadth is 16 cm. This can be written as:
  • $l + b = 16 \text{ cm}$
  • The height of the cuboid is $\frac{1}{4}$ of the sum of its length and breadth. This can be written as:
  • $h = \frac{1}{4} \times (l + b)$

Finding the Height of the Cuboid

We can substitute the given sum of length and breadth into the equation for the height:

$h = \frac{1}{4} \times (l + b)$

Since $l + b = 16 \text{ cm}$, we have:

$h = \frac{1}{4} \times 16 \text{ cm}$

Calculating the height:

$h = 4 \text{ cm}$

Calculating the Lateral Surface Area of the Cuboid

The lateral surface area (LSA) of a cuboid is the sum of the areas of its four side faces (excluding the top and bottom faces). The formula for the lateral surface area of a cuboid is:

$\text{LSA} = 2 \times \text{height} \times (\text{length} + \text{breadth})$

In terms of $l$, $b$, and $h$:

$\text{LSA} = 2h(l + b)$

We have already found that $h = 4 \text{ cm}$ and we are given that $l + b = 16 \text{ cm}$. Now, we substitute these values into the formula:

$\text{LSA} = 2 \times 4 \text{ cm} \times 16 \text{ cm}$

$\text{LSA} = 8 \text{ cm} \times 16 \text{ cm}$

$\text{LSA} = 128 \text{ cm}^2$

Therefore, the lateral surface area of the cuboid is 128 cm$^2$.

Summary of Calculations

Parameter Value/Relation Calculated Value
Sum of Length and Breadth ($l+b$) Given 16 cm
Height ($h$) $\frac{1}{4} \times (l+b)$ $\frac{1}{4} \times 16 \text{ cm} = 4 \text{ cm}$
Lateral Surface Area (LSA) $2h(l+b)$ $2 \times 4 \text{ cm} \times 16 \text{ cm} = 128 \text{ cm}^2$

Revision Table: Cuboid Formulas

Concept Formula Description
Volume $V = l \times b \times h$ Space occupied by the cuboid
Total Surface Area (TSA) $\text{TSA} = 2(lb + bh + hl)$ Sum of the areas of all six faces
Lateral Surface Area (LSA) $\text{LSA} = 2h(l + b)$ Sum of the areas of the four side faces
Diagonal $d = \sqrt{l^2 + b^2 + h^2}$ Length of the longest segment connecting opposite vertices

Additional Information: Understanding Surface Area

Surface area is a measure of the total area that the surface of a three-dimensional object occupies. For a cuboid, there are two main types of surface area often calculated: total surface area and lateral surface area.

  • Total Surface Area: This includes the area of all six faces (top, bottom, front, back, left, right).
  • Lateral Surface Area: This includes only the area of the four vertical faces (front, back, left, right). It is often referred to as the area of the walls if the base is the floor and the top is the ceiling.

In this problem, we specifically calculated the lateral surface area using the given dimensions.

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Important Questions from Solid Figures

  1. Find the volume of the cylinder whose radius is 38.5 cm and height is 18 cm. (use $\pi = 22/7$ and In $cm^3$)
  2. Find the surface area of the sphere (in $cm^2$) whose radius is 168 cm and $\pi = 22/7$.
  3. Find the volume of the cylinder whose radius is 21 cm and height is 13 cm. (In $cm^3$ and use $\pi = 22/7$)
  4. A solid spherical ball made of iron is melted and two new balls are made whose diameters are in the ratio of 1:2. The ratio of the volume of the smaller new ball to the original ball is
  5. If a cubical container of length, breadth and height each of 10 cm can contain exactly 1 litre of water, then a spherical container of radius 10.5 cm can contain

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